Explanation Given: Pt|Fe(CN) 6 4 − (4 .42 × 10 − 2 M), Fe(CN) 6 3 − (8 .93 × 10 − 3 M)||Ag + (5 .75×10 -2 M)|Ag Resistance of the galvanic cell is 3 .85 Ω Current drawn from the cell is 0.0422 A The expression for the potential of the electrolytic cell is: E = E R − E L − V ...... (I) Here, the electrode potential for cathode is E R , electrode potential for anode is E L , and the potential difference is V . The expression for the potential difference is: V = I R Here, the current flowing through the cell is I and the resistance of the cell is R . Substitute I R for V in Equation (I) E = E R − E L − I R ...... (II) The half cell reaction is: Ag + + e − ⇌ Ag ( s ) The value of standard electrode potential for the reaction is 0.799 V E R 0 = 0.799 V Here, the standard electrode potential is E R 0 . The expression for the electrode potential is: E R = E R 0 − 0.0592 n log ( 1 [ Ag + ] ) ...... (III) Here, the electrons involved in the reaction is n , the concentrations of Ag + is [ Ag + ] . Substitute 0.799 V for E R 0 in Equation (III). E R = ( 0.799 V ) − 0.0592 n log ( 1 [ Ag + ] ) ...... (IV) The half cell reaction is: Fe ( CN ) 6 3 − + e − ⇌ Fe ( CN ) 6 4- The value of standard electrode potential for the reaction is 0.36 V E L 0 = 0.36 V Here, the standard electrode potential is E L 0 . The expression for the electrode potential is: E L = E L 0 − 0.0592 n log ( [ Fe ( CN ) 6 4- ] [ Fe ( CN ) 6 3- ] ) ...... (V) Here, the electrons involved in the reaction is n , the concentrations of Fe ( CN ) 6 4- is [ Fe ( CN ) 6 4- ] and the concentrations of Fe ( CN ) 6 3- is [ Fe ( CN ) 6 3- ]

7th Edition

ISBN: 9781305577213

Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher: Cengage Learning

See similar textbooks

Question

Chapter 22, Problem 22.17QAP

Interpretation Introduction

Interpretation:

The initial potential of the given cell has to be found.

Concept introduction:

The potential difference is the driving agent for the flow of current. In an electrolytic cell, for the generation of an electric current, a sufficient potential difference is required. The resistance offered by the ions and the electrons is overcome by the potential difference. From the Ohm’s law, a potential difference is expressed as the product of current and the resistance of the cell.

Expert Solution & Answer

Chapter 22 Solutions

Principles of Instrumental Analysis

Ch. 22 - Calculate the electrode potentials of the...Ch. 22 - Prob. 22.2QAP Ch. 22 - For each of the following half-cells, compare...Ch. 22 - For each of the following half-cells, compare...Ch. 22 - Prob. 22.5QAP Ch. 22 - Calculate the electrode potentials for the...Ch. 22 - Calculate the theoretical potential of each of the...Ch. 22 - Calculate the theoretical potential of each of the...Ch. 22 - Prob. 22.9QAP Ch. 22 - Prob. 22.10QAP

Ch. 22 - Calculate the standard potential for the...Ch. 22 - Calculate the standard potential for the...Ch. 22 - From the standard potentials Tl++eTl(s)E0=0.336V...Ch. 22 - From the standard potentials...Ch. 22 - Prob. 22.15QAP Ch. 22 - Prob. 22.16QAP Ch. 22 - Prob. 22.17QAP Ch. 22 - Prob. 22.18QAP

Knowledge Booster

Similar questions

Recommended textbooks for you

Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:9781285640686
Author:Skoog
Publisher:Cengage
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,
Principles of Modern Chemistry
Chemistry
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:Cengage Learning