# Calculate the change in entropy of 250 g of water warmed slowly from 20.0°C to 80.0°C.

### Physics for Scientists and Enginee...

9th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305116399

Chapter
Section

### Physics for Scientists and Enginee...

9th Edition
Raymond A. Serway + 1 other
Publisher: Cengage Learning
ISBN: 9781305116399
Chapter 22, Problem 22.51P
Textbook Problem
1 views

## Calculate the change in entropy of 250 g of water warmed slowly from 20.0°C to 80.0°C.

To determine

The change in entropy of water.

### Explanation of Solution

The mass of the water is 250g and the temperature is changed from 20.0°C to 80.0°C.

Write the formula to find change in entropy

ΔS=(mCln(ThTc))

Here, ΔS is the entropy change, m is the mass of water, Th is the final temperature, Tc is the initial temperature and C is the specific heat of water.

Conclusion:

Substitute 250g for m, 4186J/KgK for C, 80°C for Th and 20°C for Tc in above expression to find the change in entropy

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