   Chapter 2.2, Problem 2.2CYU

Chapter
Section
Textbook Problem

Verify that the atomic weight of chlorine is 35.45, given the following information:35CL mass = 34.96885 u; percent abundance = 75.77%37Cl mass = 36.96590 u; percent abundance = 24.23%

Interpretation Introduction

Interpretation:

The average weight of chlorine has to be verified as 35.45, if the one isotope has a mass of 34.96885u in abundance 75.77% and other isotope has a mass of 36.96590u in an abundance of 24.23%

Concept introduction:

Equation for average weight is,

average weight=(%abundanceisotop-1100)×(massofisotop-1) +(%abundanceisotop-2100)×(massofisotop-2)+etc

Explanation

There are two isotopes for chlorine atom.

The mass of isotope-1 is 34.96885u and its abundance is 75.77%

The mass of isotope-2 is 36.96590u and its abundance is 24.23%

Equation for average weight is,

average weight=(%abundanceisotop-1100)×(massofisotop-1) +(%abundanceisotop-2100

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