   Chapter 2.2, Problem 32E

Chapter
Section
Textbook Problem

In Exercises 31-34, evaluate h(2), where h = g ∘ f.32. f ( x ) = x 2 − 1 3 ; g ( x ) = 3 x 3 + 1

To determine
The value of the given function.

Explanation

Given:

The function f(x)=x213 , g(x)=3x3+1 and h=gf .

Calculation:

Let f and g be functions, then the composition of function is defined by,

(gf)(x)=g(f(x)) (1)

Substitute x213 for x in g(x) and h(x) for gf to evaluate the value of h(x) .

(gf)(x)=g(f(x))h(x)=3(f(x))3+1=3(x213)3+1=3((x

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