College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 23, Problem 28P

Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin θ1 = n2 sin θ2. For paraxial rays, we assume θ1 and θ2 are small, so we may write n1 tan θ1n2 tan θ2. The magnification is defined as M = h′/h. Prove that the magnification is given by M = –n1q/n2p.

Chapter 23, Problem 28P, Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a

Figure P23.28

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Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2 . The surface forms an image  I of object o. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin θ1 = n2 sin02 . For paraxial rays, we assume θ1 and θ2 are small, so we may write n1 tan θ1 = n2 tan θ2. The magnification is defined as M =h′/h. Prove that the magnification is given by M = −n1 q/n2p.

Chapter 23 Solutions

College Physics

Ch. 23 - Construct ray diagrams to determine whether each...Ch. 23 - Prob. 6CQCh. 23 - Suppose you want to use a converging lens to...Ch. 23 - Lenses used in eyeglasses, whether converging or...Ch. 23 - In a Jules Verne novel, a piece of ice is shaped...Ch. 23 - If a cylinder of solid glass or clear plastic is...Ch. 23 - Prob. 11CQCh. 23 - Prob. 12CQCh. 23 - Why does the focal length of a mirror not depend...Ch. 23 - A person spear fishing from a boat sees a...Ch. 23 - An object represented by a gray arrow, is placed...Ch. 23 - (a) Does your bathroom mirror show you older or...Ch. 23 - Suppose you stand in front of a flat mirror and...Ch. 23 - Prob. 3PCh. 23 - In a church choir loft, two parallel walls are...Ch. 23 - A periscope (Fig. P23.5) is useful for viewing...Ch. 23 - A dentist uses a mirror to examine a tooth that is...Ch. 23 - A convex spherical mirror, whose focal length has...Ch. 23 - To fit a contact lens to a patient's eye, a...Ch. 23 - A virtual image is formed 20.0 cm from a concave...Ch. 23 - While looking at her image in a cosmetic minor,...Ch. 23 - Prob. 11PCh. 23 - A dedicated sports car enthusiast polishes the...Ch. 23 - A concave makeup mirror it designed to that a...Ch. 23 - A 1.80-m-tall person stands 9.00 m in front of a...Ch. 23 - A man standing 1.52 m in front of a shaving mirror...Ch. 23 - Prob. 16PCh. 23 - At an intersection of hospital hallways, a convex...Ch. 23 - The mirror of a solar cooker focuses the Suns rays...Ch. 23 - A spherical mirror is to be used to form an image,...Ch. 23 - Prob. 20PCh. 23 - A cubical block of ice 50.0 cm on an edge is...Ch. 23 - A goldfish is swimming inside a spherical bowl of...Ch. 23 - A paperweight is made of a solid hemisphere with...Ch. 23 - The top of a swimming pool is at ground level. If...Ch. 23 - A transparent sphere of unknown composition is...Ch. 23 - A man inside a spherical diving bell watches a...Ch. 23 - A jellyfish is floating in a water-filled aquarium...Ch. 23 - Figure P23.28 shows a curved surface separating a...Ch. 23 - A contact lens is made of plastic with an index of...Ch. 23 - A thin plastic lens with index of refraction n =...Ch. 23 - A converging lens has a local length of 10.0 cm....Ch. 23 - Prob. 32PCh. 23 - A diverging lens has a focal length of magnitude...Ch. 23 - A diverging lens has a focal length of 20.0 cm....Ch. 23 - Prob. 35PCh. 23 - The nickels image in Figure P23.36 has twice the...Ch. 23 - An object of height 8.00 cm it placed 25.0 cm to...Ch. 23 - An object is located 20.0 cm to the left of a...Ch. 23 - A converging lens is placed 30.0 cm to the right...Ch. 23 - (a) Use the thin-lens equation to derive an...Ch. 23 - Two converging lenses, each of focal length 15.0...Ch. 23 - A converging lens is placed at x = 0, a distance d...Ch. 23 - A 1.00-cm-high object is placed 4.00 cm to the...Ch. 23 - Two converging lenses having focal length of f1 =...Ch. 23 - Lens L1 in figure P23.45 has a focal length of...Ch. 23 - An object is placed 15.0 cm from a first...Ch. 23 - Prob. 47APCh. 23 - Prob. 48APCh. 23 - Prob. 49APCh. 23 - Prob. 50APCh. 23 - The lens and the mirror in figure P23.51 are...Ch. 23 - The object in Figure P23.52 is mid-way between the...Ch. 23 - Prob. 53APCh. 23 - Two rays travelling parallel to the principal axis...Ch. 23 - To work this problem, use the fact that the image...Ch. 23 - Consider two thin lenses, one of focal length f1...Ch. 23 - An object 2.00 cm high is placed 10.0 cm to the...Ch. 23 - Prob. 58APCh. 23 - Figure P23.59 shows a converging lens with radii...Ch. 23 - Prob. 60APCh. 23 - The lens-makers equation for a lens with index n1...Ch. 23 - An observer to the right of the mirror-lens...Ch. 23 - The lens-markers equation applies to a lens...Ch. 23 - Prob. 64APCh. 23 - A glass sphere (n = 1.50) with a radius of 15.0 cm...Ch. 23 - An object 10.0 cm tall is placed at the zero mark...
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