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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

Complete and balance the following equations:

(a) C6H5NH2() + HCl(aq) →

(b) (CH3)3N(aq) + H2SO4(aq) →

(a)

Interpretation Introduction

Interpretation: The given reaction has to be completed and balanced rightfully.

C6H5NH2(l)+HCl(aq)?

Concept introduction:

The reaction of an amine with an acid is knwon as acid-base reaction. An amine has lone pair of electrons which acts as a base and accepts the proton and the salt formtaion takes place.

A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.

A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.

Explanation

The given reaction of aniline with hydrochloric acid is the acid base reaction. The lone pair of N in aniline abstract the H+ from hydrochloric acid and a salt C6H5NH3Cl formation takes place.

The complete reaction can be represented as follows,

C6H

(b)

Interpretation Introduction

Interpretation: The given reaction has to be completed and balanced rightfully.

(CH3)3N(aq)+H2SO4(aq)?

Concept introduction:

The reaction of an amine with an acid is knwon as acid-base reaction. An amine has lone pair of electrons which acts as a base and accepts the proton and the salt formtaion takes place.

A chemical equation consists of reactants and products. The two are separated by an arrow. Each substances of reactants and products are separated from other by a plus sign. The reactants lies on left hand side while products lies on right hand side of the reaction.

A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.

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Chapter 23 Solutions

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Sect-23.5 P-1.3ACPSect-23.5 P-2.1ACPSect-23.5 P-2.2ACPSect-23.5 P-2.3ACPSect-23.5 P-3.1ACPSect-23.5 P-3.2ACPSect-23.5 P-3.3ACPSect-23.5 P-3.4ACPSect-23.5 P-3.5ACPCh-23 P-1PSCh-23 P-2PSCh-23 P-3PSCh-23 P-4PSCh-23 P-5PSCh-23 P-6PSCh-23 P-7PSCh-23 P-8PSCh-23 P-9PSCh-23 P-10PSCh-23 P-11PSCh-23 P-12PSCh-23 P-13PSCh-23 P-14PSCh-23 P-15PSCh-23 P-16PSCh-23 P-17PSCh-23 P-18PSCh-23 P-19PSCh-23 P-20PSCh-23 P-21PSCh-23 P-22PSCh-23 P-23PSCh-23 P-24PSCh-23 P-25PSCh-23 P-26PSCh-23 P-27PSCh-23 P-28PSCh-23 P-29PSCh-23 P-30PSCh-23 P-31PSCh-23 P-32PSCh-23 P-33PSCh-23 P-34PSCh-23 P-35PSCh-23 P-36PSCh-23 P-37PSCh-23 P-38PSCh-23 P-39PSCh-23 P-40PSCh-23 P-41PSCh-23 P-42PSCh-23 P-43PSCh-23 P-44PSCh-23 P-45PSCh-23 P-46PSCh-23 P-47PSCh-23 P-48PSCh-23 P-49PSCh-23 P-50PSCh-23 P-51PSCh-23 P-52PSCh-23 P-53PSCh-23 P-54PSCh-23 P-55PSCh-23 P-56PSCh-23 P-57PSCh-23 P-58PSCh-23 P-59PSCh-23 P-60PSCh-23 P-61PSCh-23 P-62PSCh-23 P-63PSCh-23 P-64PSCh-23 P-65PSCh-23 P-66PSCh-23 P-67PSCh-23 P-68PSCh-23 P-69PSCh-23 P-70PSCh-23 P-71PSCh-23 P-72PSCh-23 P-73PSCh-23 P-74PSCh-23 P-75GQCh-23 P-76GQCh-23 P-77GQCh-23 P-78GQCh-23 P-79GQCh-23 P-80GQCh-23 P-81GQCh-23 P-82GQCh-23 P-83GQCh-23 P-84GQCh-23 P-85GQCh-23 P-86GQCh-23 P-87GQCh-23 P-88GQCh-23 P-89GQCh-23 P-90GQCh-23 P-91GQCh-23 P-92GQCh-23 P-93GQCh-23 P-94GQCh-23 P-95GQCh-23 P-96GQCh-23 P-97GQCh-23 P-98GQCh-23 P-99GQCh-23 P-100GQCh-23 P-101GQCh-23 P-102GQCh-23 P-103ILCh-23 P-104ILCh-23 P-105ILCh-23 P-106ILCh-23 P-107ILCh-23 P-108ILCh-23 P-109ILCh-23 P-110ILCh-23 P-111ILCh-23 P-112ILCh-23 P-113ILCh-23 P-114ILCh-23 P-115SCQCh-23 P-116SCQCh-23 P-117SCQCh-23 P-118SCQCh-23 P-119SCQCh-23 P-120SCQCh-23 P-121SCQ

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