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The 5.00 A current through a 1.50 H inductor is dissipated by a 2.00 ( resistor in a circuit like that in Figure 23.44 with the switch in position 2. (a) What is the initial energy in the inductor? (b) How long will it take the current to decline to 5.00% of its initial value? (c) Calculate the average power dissipated, and compare it with the initial power dissipated bythe resistor.

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College Physics

1st Edition
Paul Peter Urone + 1 other
Publisher: OpenStax College
ISBN: 9781938168000

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Section
BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
Publisher: OpenStax College
ISBN: 9781938168000
Chapter 23, Problem 76PE
Textbook Problem
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The 5.00 A current through a 1.50 H inductor is dissipated by a 2.00 ( resistor in a circuit like that in Figure 23.44 with the switch in position 2. (a) What is the initial energy in the inductor? (b) How long will it take the current to decline to 5.00% of its initial value? (c) Calculate the average power dissipated, and compare it with the initial power dissipated bythe resistor.

Chapter 23, Problem 76PE, The 5.00 A current through a 1.50 H inductor is dissipated by a 2.00 ( resistor in a circuit like

To determine

(a)

The initial energy in the inductor.

Explanation of Solution

Given info:

The 5.00 A current through a 1.50 H inductor is dissipated by a 2.00 resistor in a circuit like that in Figure 23.44 with the switch in position 2.

Formula used:

The energy stored in inductor is given by

  Eindc=12LI2

Here, I is current and L is the self-inductance of inductor.

Calculation:

We have,  L=1.50H and I=5

To determine

(b)

How long will it take the current to decline to 5.00% of its initial value?

To determine

(c)

The average power dissipated and compare it with the initial power dissipated by the resistor.

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Chapter 23 Solutions

College Physics
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