(a)
Interpretation:
The moles of NaOH solution is to be calculated.
Concept introduction:
Number of moles can be calculated as to multiply the molarity by the volume in liters.
It is expressed as,
Answer to Problem 1ASA
The moles of NaOH solution is 0.0432 mol.
Explanation of Solution
Volume of initial NaOH solution, (V1) = 7.2 mL= 0.0072 L
Molarity of NaOH solution, (M1) = 6.0 M
Volume of final NaOH solution, (V2) = 400.0 mL= 0.4 L
First we have to find the moles of NaOH, it is calculated as
Substitute the values of molarity and volume of NaOH in the above expression.
The number of moles of
(b)
Interpretation:
The molarity of resulting solution is to be calculated.
Concept introduction:
Molarity is defined as number of moles of solute dissolved in 1 liter of solution.
It is expressed as,
Answer to Problem 1ASA
The molarity of resulting solution is 0.108 M.
Explanation of Solution
To find the molarity of NaOH solution, (M2):
Calculate the molarity of NaOH solution using the final volume of NaOH.
Substitute the values of moles of NaOH and final volume of NaOH solution (V2).
We also calculate the molarity of NaOH solution as
Therefore, the molarity of resulting solution is 0.108 M.
The molarity of resulting solution is 0.108 M.
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Chapter 24 Solutions
Chemical Principles in the Laboratory
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- Chemical Principles in the LaboratoryChemistryISBN:9781305264434Author:Emil Slowinski, Wayne C. Wolsey, Robert RossiPublisher:Brooks Cole