The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 24, Problem 1CQ

The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.

Chapter 24, Problem 1CQ, The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge

Expert Solution & Answer

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

A charge in constant, uniform electric and magnetic fields gets accelerated in the direction of the magnetic field. gets accelerated in the direction of the electric field.

Why is the direction of lightning from cloud to cloud and cloud to ground? What do you think is the reason behind the thickness of the cable used in our power lines?

In Maglev trains, fields exist between objects that are not in contact but can interact at a distance. True or False?

Answer 2

Textbook Question

Chapter 24, Problem 1CQ

The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.

Chapter 24, Problem 1CQ, The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge

Expert Solution & Answer

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 24, Problem 1CQ

The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.

Chapter 24, Problem 1CQ, The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge

Expert Solution & Answer

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 24, Problem 1CQ

The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.

Chapter 24, Problem 1CQ, The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge

Expert Solution & Answer

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Answer 8

Expert Solution & Answer

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The direction of the electric field shown in each part of Figure is that produced by the charge distribution in the wire.

Answer 12

Answer to Problem 1CQ

The direction of the electric field is upward
The value of electric field is zero.
The direction of the electric field is downward
The direction of the electric field is upward

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 1

Explanation:

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Answer 13

Explanation of Solution

Given info:

Justify the direction shown in each part, using the Coulomb force law and the definition of E=F/q, where q is a positive test charge?

College Physics, Chapter 24, Problem 1CQ , additional homework tip 2

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

The distances between the positive and negative charge in part b is zero, so the electric field value is zero, so there is direction.

Positive charge moves from positive to negative, so the direction of electric field in part c is towards downward direction.

Positive charge moves from positive to negative, so the direction of electric field in part a is towards upper direction.

Conclusion:

The direction of the electric field shown in each part of Figure is studied.

Answer 14

Ch. 24 - The direction of the electric field shown in each...Ch. 24 - Is the direction of the magnetic field shown in...Ch. 24 - Why is the direction of the current shown in each...Ch. 24 - In which situation shown in Figure 24.24 will the...Ch. 24 - In which situation shown in Figure 24.25 will the...Ch. 24 - Should the straight wire antenna of a radio he...Ch. 24 - Under what conditions might wires in a DC circuit...Ch. 24 - Give an example of interference of electromagnetic...Ch. 24 - Figure 24.26 shows the interference pattern of two...Ch. 24 - Can an antenna be any length? Explain your answer.

The direction of the electric field shown in each part of Figure 24.5 is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.

Concept explainers

Videos

Answer to Problem 1CQ

Explanation of Solution

Want to see more full solutions like this?

Chapter 24 Solutions

Additional Science Textbook Solutions