Chapter 2.4, Problem 2.8QQ

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# A skydiver jumps out of a hovering helicopter. A few seconds later, another skydiver jumps out, so they both fall along the same vertical line relative to the helicopter. Assume both skydivers fall with the same acceleration. Does the vertical distance between them (a) increase, (b) decrease, or (c) stay the same? Does the difference in their velocities (d) increase, (e) decrease, or (f) stay the same?

To determine
The vertical distance between the skydivers and difference in their velocities.

Explanation

Velocity of the object increases the positive acceleration acting on it. The velocity is the change in position. The object with a high velocity covers more distance than the object with a less distance.

The acceleration of the object when it is moving upwards under the gravity is equal to the acceleration due to gravity. However, the direction of the acceleration will be opposite to the direction of motion which slows down the object. The acceleration of freely falling object is equal to the acceleration due to gravity. The magnitude of acceleration due to gravity is 9.81â€‰m/s2 .

The first skydiver starts from a zero velocity and increases his speed due to the positive acceleration acting on him. The acceleration is equal to the acceleration due to gravity. The velocity of the second sky diver is also zero when he is at the starting height. The velocity of the first diver is greater when the second diver is at the starting height.

The velocity of both divers increases at a constant rate. Therefore, the first diver has the greater velocity always than the second diver. The second diver covers less distance compared to the first diver. Therefore, the distance between the divers keeps on increasing with time. Thus, the choice (a) is correct

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