BIOLOGY VOL. II
16th Edition
ISBN: 9781308795317
Author: Raven
Publisher: Mcgraw-Hill/Create
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Chapter 24, Problem 2A
Summary Introduction
Introduction:
Non coding DNA or junk DNA is a non functional part of the gene that does not code for any protein. It occurs usually in the repetitive sequences of the
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Which of the following experimental results was NOT evidence that DNA is the genetic molecule rather than proteins?
a.
When a virus was radioactively labelled, and the virus was allowed to infect a bacteria cell, radioactive virus DNA was found inside the bacteria cell while radioactive virus proteins were found outside the cell.
b.
Dead pathogenic bacteria cells combined with living nonpathogenic bacteria cells caused the creation of living pathogenic cells and thus the death of the host animal.
c.
Proteins are a class of macromolecules with the diversity and specificity needed for hereditary material.
d.
Nucleotide bases occur regularly, such that the number of adenines = number of thymines, and the number of guanines = number of cytosines.
Place the steps of sanger sequencing in order.A. A fluorescent laser excites the fragments and records the wavelength consistent with a single nucleotide.
B. ddNTPs bind and stop chain extension.C. DNA fragments are separated by size through a capillary tube.
D. DNA polymerase copies the target region of template DNA.E. The final nucleotide of each fragment is labeled with a fluorescent tag.
A researcher sequences the genome of a variety of bacterial and eukaryotic cells. She finds that the bacterial genome is smaller, but that there are more genes for a given number of base pairs in the eukaryotic cells. In other words, there are fewer genes per unit of length of DNA in the eukaryotic cells. What do you predict she will find if she examines the DNA more closely?
A. All of the bacterial DNA consists of coding sequences, but this is not true of the eukaryotic DNA.
B. There are more repetitive sequences in the eukaryotic DNA than in the bacterial DNA.
C. There are densely packed genes in the eukaryotic DNA that were not immediately distinguishable during the first analysis.
D. The bacteria have larger quantities of noncoding DNA than the eukaryotic cells.
Chapter 24 Solutions
BIOLOGY VOL. II
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- a. The reading frame DNA sequence is b. The mRNA sequence is c. The polypeptide sequence is a.The mutated polypeptide sequence is b.What kind of mutation was produced?arrow_forwardFor each example: a. fill in the complimentary DNA strand b. fill in the correct mRNA bases by transcribing the bottom DNA code c. fill in the correct tRNA bases d. translate the MRNA codons to find the correct amino acids Example #1 5' 3' (A (A DNA MRNA TRNA Amino Acidsarrow_forwardConsider the following segment of DNA:5′ GCTTCCCAA 3′3′ CGAAGGGTT 5′Assume that the top strand is the template strand usedby RNA polymerase.a. Draw the RNA transcribed.b. Label its 5′ and 3′ ends.c. Draw the corresponding amino acid chain.d. Label its amino and carboxyl ends.Repeat parts a through d, assuming the bottom strand tobe the template strand.arrow_forward
- If you repeat the okazaki experiment WITHOUT denaturing DNA, what would be the expected outcome? a. Increased length of RNA primers b. Slowing of fragment maturation O c. No short fragments observed d. All short fragments observed e. Decrease in fragment size over timearrow_forwardShown below is diagram of RNA polymerase undergoing the process of transcription: This transcript: O Select one: a. None of these choices is correct. O b. has a sequence complementary to the top strand of the DNA. c. has a sequence identical to the top strand of the DNA. d. has a sequence complementary to the bottom strand of the DNA. e. has a sequence identical to the bottom strand of the DNA. f. It is not possible to determine, because not enough information has been provided. g. More than one of these choices is correct. MacEarrow_forward1) Where in the heck did Class I transposons originate? a DNA mutations. b Bacteria. c Prophages. d Retroviruses. 2) What do you think about humans only having about 22,500 genes but we contain about 100,000 proteins?! a The production of quaternary shape in proteins can contribute to protein variation. b That's the work of the spliceosome! c Post-translation modifications in the Golgi Apparatus are responsible for some of that. d All the answers are correct.arrow_forward
- You obtained the sequence of the frog gene X you amplified in Question #16 through a process called automated sequencing. In automated sequencing, you are given a printout of the sense strand of your DNA. The first thing you need to do is use the correct reading frame. Having done this, the next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence. a.The reading frame DNA sequence is: b.The mRNA sequence is: c.The polypeptide sequence is: A disease in frogs which causes their tongue to fall out of their mouths is killing the frog population in LA County. You obtain a dead frog and isolate its gene Xf. When you sequence this mutated gene, you find that the last ‘G’ at the end of the first line of this sequence has been deleted (i.e. the G at position 86). In order to determine how this mutation changes the resulting polypeptide, write the mutated polypeptide sequence in the space below. What kind of…arrow_forwardWhich of the following statements are NOT true? A. Replication is the process of making DNA and takes place in the nucleus of prokaryotic cells. B. Translation produces a polypeptide that may require additional processing to become a functional protein C. Transcription starts at the promoter of eukaryotic cells and scans until reaches the start codon. D. Splicing results in exons being put together and introns being removedarrow_forwardCertain restriction endonucleases produce cohesive (sticky) ends. This means that they: a. stick tightly to the ends of the DNA they have cut. b. cut both DNA strands at the same base pair. c. make a staggered double-strand cut, leaving ends with a few nucleotides of single-stranded DNA protruding. d. cut in regions of high GC content, leaving ends that can form more hydrogen bonds than ends of high AT content. e. cut in regions of high AT content, leaving ends that can form more hydrogen bonds than ends of high GC content.arrow_forward
- What is Sanger sequencing? Why do we use ddNTP? How to read a DNA sequence gel? c. What is a cDNA seq (RNA seq)? d. What is the main difference between a genomic and a transcriptome study?arrow_forwardHow can you design your RT-PCR experiment to control for gDNA contamination? A. Use forward and reverse primers that bind to the same exon. B. Run a control lane where only RT was performed and not PCR. C. Run a control lane where MRNA has been amplified using PCR. D. Use forward and reverse primers that span the junction of 2 separate exons.arrow_forwardWhich of the following statements is TRUE concerning the synthesis of the leading and lagging strands of DNA in prokaryotic cells? a. O b. The leading strand is synthesized by one polymerase III continuously, and the lagging strand is synthesized by several molecules of DNA polymerase III. d. The leading and lagging strands are synthesized at the same time by the one DNA polymerase I. O c. The leading and lagging strands are synthesized at the same time by the one DNA polymerase III. The leading strand is synthesized by one polymerase III, and the lagging strand is synthesized by DNA polymerase I.arrow_forward
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