In Figure 24.1, two points Ⓐ and Ⓑ are located within a region in which there is an electric field. (i) How would you describe the potential difference Δ V = V Ⓑ − V Ⓐ ? (a) It is positive. (b) It is negative. (c) It is zero. (ii) A negative charge is placed at Ⓐ and then moved to Ⓑ. How would you describe the change in potential energy of the charge–field system for this process? Choose from the same possibilities. Figure 24.1 (Quick Quiz 24.1) Two points in an electric field.

Question

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Answer 1

Textbook Question

Chapter 25, Problem 25.1QQ

In Figure 24.1, two points Ⓐ and Ⓑ are located within a region in which there is an electric field. (i) How would you describe the potential difference ΔV = V_Ⓑ − V_Ⓐ? (a) It is positive. (b) It is negative. (c) It is zero. (ii) A negative charge is placed at Ⓐ and then moved to Ⓑ. How would you describe the change in potential energy of the charge–field system for this process? Choose from the same possibilities.

Figure 24.1 (Quick Quiz 24.1) Two points in an electric field.

Chapter 25, Problem 25.1QQ, In Figure 24.1, two points and are located within a region in which there is an electric field.

(a)

Expert Solution

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer to Problem 25.1QQ

Option (b). It is negative.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

(b)

Expert Solution

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer to Problem 25.1QQ

Option (a). It is positive.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.

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Answer 2

Textbook Question

Chapter 25, Problem 25.1QQ

In Figure 24.1, two points Ⓐ and Ⓑ are located within a region in which there is an electric field. (i) How would you describe the potential difference ΔV = V_Ⓑ − V_Ⓐ? (a) It is positive. (b) It is negative. (c) It is zero. (ii) A negative charge is placed at Ⓐ and then moved to Ⓑ. How would you describe the change in potential energy of the charge–field system for this process? Choose from the same possibilities.

Figure 24.1 (Quick Quiz 24.1) Two points in an electric field.

Chapter 25, Problem 25.1QQ, In Figure 24.1, two points and are located within a region in which there is an electric field.

(a)

Expert Solution

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer to Problem 25.1QQ

Option (b). It is negative.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

(b)

Expert Solution

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer to Problem 25.1QQ

Option (a). It is positive.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.

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Answer 3

Textbook Question

Chapter 25, Problem 25.1QQ

In Figure 24.1, two points Ⓐ and Ⓑ are located within a region in which there is an electric field. (i) How would you describe the potential difference ΔV = V_Ⓑ − V_Ⓐ? (a) It is positive. (b) It is negative. (c) It is zero. (ii) A negative charge is placed at Ⓐ and then moved to Ⓑ. How would you describe the change in potential energy of the charge–field system for this process? Choose from the same possibilities.

Figure 24.1 (Quick Quiz 24.1) Two points in an electric field.

Chapter 25, Problem 25.1QQ, In Figure 24.1, two points and are located within a region in which there is an electric field.

(a)

Expert Solution

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer to Problem 25.1QQ

Option (b). It is negative.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

(b)

Expert Solution

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer to Problem 25.1QQ

Option (a). It is positive.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.

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Answer 4

Textbook Question

Chapter 25, Problem 25.1QQ

In Figure 24.1, two points Ⓐ and Ⓑ are located within a region in which there is an electric field. (i) How would you describe the potential difference ΔV = V_Ⓑ − V_Ⓐ? (a) It is positive. (b) It is negative. (c) It is zero. (ii) A negative charge is placed at Ⓐ and then moved to Ⓑ. How would you describe the change in potential energy of the charge–field system for this process? Choose from the same possibilities.

Figure 24.1 (Quick Quiz 24.1) Two points in an electric field.

Chapter 25, Problem 25.1QQ, In Figure 24.1, two points and are located within a region in which there is an electric field.

(a)

Expert Solution

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer to Problem 25.1QQ

Option (b). It is negative.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

(b)

Expert Solution

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer to Problem 25.1QQ

Option (a). It is positive.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer to Problem 25.1QQ

Option (b). It is negative.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

(b)

Expert Solution

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer to Problem 25.1QQ

Option (a). It is positive.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.

Answer 8

(a)

Expert Solution

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer to Problem 25.1QQ

Option (b). It is negative.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The description that potential difference ΔV=VB−VA is whether positive, negative, or zero.

Answer 13

Answer to Problem 25.1QQ

Option (b). It is negative.

Answer 14

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. Thus, the potential difference ΔV=VB−VA is negative as the value of VB is lower than the value of VB . Hence, the potential difference ΔV is negative.

Conclusion:

The potential difference between the points A and B is negative as the potential of point B is at the lower value. Thus, option (b) is correct.

The potential difference between the point A and B cannot be positive because the potential of point B is at the lower value. Thus, option (a) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus, option (a) is incorrect.

Answer 15

(b)

Expert Solution

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer to Problem 25.1QQ

Option (a). It is positive.

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

The description for the change in potential energy of the charge-field system if a negative charge is paced at point A and then moved to B.

Answer 20

Answer to Problem 25.1QQ

Option (a). It is positive.

Answer 21

Explanation of Solution

The point B is the point in the electric field having lower potential value as compared to the potential value of point A. The potential difference between the points A and B is negative. The change in the potential energy is ΔU=q×ΔV . When a negative charge is moved through the field of negative potential difference then the change in the value of potential difference is positive.

Conclusion:

Therefore, the change in potential energy of the charge-field system is positive if a negative charge is paced at point A and then moved to B. Thus, option (a) is correct.

The change in potential energy of the charge field potential cannot be negative because the movement of negative charge led to change in potential energy for the positive. Thus, option (b) is incorrect.

The potential difference between the point A and B cannot be zero because the potential of point B and point A is not equal to each other. Thus the change in potential energy of charge field cannot be zero. Thus, option (c) is incorrect.