Chapter 25, Problem 38PS

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

Calculate the binding energy per mole of nucleons for nitrogen-14. The mass of nitrogen-14 is 14.003074.

Interpretation Introduction

Interpretation: The binding energy per mole of nucleons for nitrogen-14 has to be calculated.

Concept introduction:

Binding energy is the energy required to separate the nucleus of an atom into proton and neutron. Binding energy is given by Eb=Δm×(c)2, where Δm is the mass defect and c is the velocity of light =3×108m/sec-1

Mass defect is the sum of the masses of the individual nucleons that form an atomic nucleus and the mass of the nucleus.

Binding energy per nucleon =TotalbindingenergyofnucleusNumberofnucleonsinthenucleus

Explanation

Given,

The mass of calcium-40=39.962589

The mass of proton=1.00783

The mass of neutrons=1.00867

Number of proton=7=7Ã—1.00783=7.05481

Number of neutron=7= 7Ã—1.00867=7.06069

Masses of the individual nucleons=7.05481+7.06069=14.1155

The mass of nitrogen-14 is 14.003074.

Mass defect Î”m=Mâˆ’m

Î”m=Mâˆ’m=14.1155âˆ’14.003074=14.0030Î”m=0.1125g/mol=1.125Ã—10âˆ’4kg/mol

Binding energy:

Eb=Î”mÃ—(c)2=Â Â 1.125Ã—10-4kg/molÃ—(3Ã—108m/s)2=1.0125Ã—1013J=1.0125Ã—1010kJ

The binding energy for nitrogen-14 is 1

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started