   Chapter 25, Problem 42PS

Chapter
Section
Textbook Problem

Phosphorus-32 is used in the form of Na2HPO4 in the treatment of chronic myeloid leukemia, among other things.(a) The isotope decays by β-particle emission. Write a balanced equation for this process.(b) The half-life of 32P is 14.3 days. If you begin with 4.8 μg of radioactive 32P in the form of Na2HPO4, what mass remains after 28.6 days (about 1 month)?

(a)

Interpretation Introduction

Interpretation: Equation for phosphorus-32 decays by β particle emission has to be written.

Concept introduction:

In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.

Explanation

The radioactive isotope of phosphorus-32is converted into sulpher-32 isotope by the emission of beta particle. In this nuclear decay atomic number only changed there is no change in atomic mass. In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.

Equation is as follows,

P1532

(b)

Interpretation Introduction

Interpretation:

The remaining mass of phosphorus-32 isotope after 28.6days has to be calculated.

Concept introduction:

Half–life period: It is the time required for the reactant (substrate) concentration to reduce to the one-half of its initial concentration.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 