Chemistry & Chemical Reactivity
Solutions
Chemistry & Chemical Reactivity
Phosphorus-32 is used in the form of Na2HPO4 in the treatment of chronic myeloid leukemia, among other things.
(a) The isotope decays by β-particle emission. Write a balanced equation for this process.
(b) The half-life of 32P is 14.3 days. If you begin with 4.8 μg of radioactive 32P in the form of Na2HPO4, what mass remains after 28.6 days (about 1 month)?
(a)
Interpretation: Equation for phosphorus-32 decays by
Concept introduction:
In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
The radioactive isotope of phosphorus-32is converted into sulpher-32 isotope by the emission of beta particle. In this nuclear decay atomic number only changed there is no change in atomic mass. In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
Equation is as follows,
(b)
Interpretation:
The remaining mass of phosphorus-32 isotope after 28.6days has to be calculated.
Concept introduction:
Half–life period: It is the time required for the reactant (substrate) concentration to reduce to the one-half of its initial concentration.
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