A rectangular surface extends from x = 0 to x = 36.0 cm and from y = 0 to y = 30.0 cm in the xy plane in a region of space permeated by a nonuniform electric field given by E = (4.00z + 3.00y − 2.00x) N/C. What is the electric flux through the surface

A rectangular surface extends from x = 0 to x = 36.0 cm and from y = 0 to y = 30.0 cm in the xy plane in a region of space permeated by a nonuniform electric field given by E = (4.00z + 3.00y − 2.00x) N/C. What is the electric flux through the surface

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

See similar textbooks

Related questions

Q: An electric field of 600N/C makes an angle of 20.00 with the surface vector, which has a magnitude…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.60 ×…

Q: We have an electric flux of magnitude 141 Nm2/ C passing through a flat horizontal surface with an…

Q: A closed surface with dimensions a-b%3D0.40m and c=0.60 m is located as in the figure below. The…

A: NOTE-as per our company guidelines we are supposed to answer ?️only first 3 sub-parts. Kindly repost…

Q: Calculate the electric flux for each of the closed surfaces a, b, c, and d. d. 92 93 97 94 95 98 96…

A: From Gauss's law, the electric flux through a closed surface can be given by, φ=qencε0, where qenc…

Q: A nonuniform electric field is given by the expression D = 2у a + z a — Зха y C/m?. Determine the…

A: We have Electric field given by D=2yi^+zj^-3xk^. We need to find Electric flux through a rectangular…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

Q: 30 cm E 60° 10 cm Consider a closed triangular box resting within a horizontal electric field of…

A: The given values are,

Q: what conditions must be true for you to be allowed to write the flux integral such that... §Ē • dÃ =…

A: Electric flux: The total number of electric field lines passing the area per unit time is known as…

Q: A flat surface of area 1.25 m2 is rotated through a uniform horizontal electric field of 4.20 N/C.…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

Q: he total electric flux through a closed cylindrical (length = 1.2 m, diameter = 0.20 m) surface is…

A: Given:- The Total electric flus is -5.0 Nm2/C The length of the cylinder L = 1.2 m The diameter…

Q: d P

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.54 x…

A: Given: Now,

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

Q: A uniform electric field with a magnitude of 1.25x105 N/C passes through a rectangle with sides of…

Q: A closed surface with dimensions a=b=D0.40 m and c=0.60 m is located as in the figure below. The…

Q: 15.7c Consider a closed triangular box resting within a horizontal electric field of magnitude E =…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.22 x…

A: Magnetic flux

Q: A circular surface with a radius of 0.063 m is exposed to a uniform electric field of magnitude 1.76…

A: Given that :E=1.76 x 104 N/Cr=0.063 mϕ=58 Nm2/Cwhere,E is the electric fieldr is the radius of the…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.86 ×…

A: Magnitude of electric field through the surface Height of the inclination Width of the inclination…

Q: A uniform electric field with a magnitude of 650 N/C incident on a plane circular surface of area of…

A: Given: The strength of the electric field is 650 N/C. The radius of the circular shape is 35 cm =…

Q: A 3.7 cm × 4.0 cm rectangle lies in the xy-plane. What is the electric flux through the rectangle…

A: Given:

Q: Find the electric flux through the plane surface shown in the figure below if 0 = 61.8°, E = 372…

Q: What is the total flux passing through a 10 cm x 6 cm surface in a region where the electric flux…

A: GIven data: The area of the surface is A=10 cm×6 cm=60 cm2. The electric flux density is E=2700…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.04 ×…

A: Given , Electric field = 7.04 × 10^4 N/C

Q: he electric flux (Φ) that passes through this surface

A: we know electric flux ϕ = E·A =EAcosθ where θ= angle between electric field and area vector A = area…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.86 x…

Q: A closed surface with dimensions a=b=0.40 m and c=0.60 m is located as in the figure below. The left…

Q: uniform electric field of magnitude E=435 N/C makes an angle of θ= 65.0 ° with a plane surface of…

A: Given Electric field E = 435 N/C Area A = 3.50 m2 Angle = 650

Q: A circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

A: Given : E=(3+57x2)i N/C a=b=0.40 m c=0.60 m We have to fins the net flux leaving the closed surface.

Q: An electric field of magnitude 4.44 kN/C is applied along the x axis. Calculate the electric flux…

A: Given data- electric field magnitude E=4.44 kN/C is applied along x axis. A rectangular plate 0.350…

Q: A closed surface with dimensions a=b%=D0.40 m and c=0.60 m is located as in the figure below. The…

A: The electric flux is given by the product of surface area and the component of electric field…

Q: A rectangular sheet with length 5.00 m and width 3.00 m is immersed in a uniform electric field with…

A: Given:Length of the rectangular sheet, l = 5 mwidth of the rectangular sheet, b= 3mElectric field,…

Q: A disk of radius 132mm is oriented with its normal unit vector at 30 degrees to a uniform electric…

A: Given Data: The radius of the disk, R=132 mm.=132×10-3m The magnitude of the electric field,…

Q: A circular surface with a radius of 0.062 m is exposed to a uniform electric field of magnitude 1.58…

A: Radius of circular surface (R) = 0.062 m Area of circular surface (A) = π(R)2 = π×(0.062)2 =…

Q: A uniform horizontal electric field of E = (136 Î +71 Ĵ) N/C passes through an inclined plane that…

A: ☆ Given value --- electric field of E = (136 Î +71 Ĵ) N/C . plane that is 52 cm wide and 88 cm…

Q: Calculate the electric flux for each of the following sets of variables. (a) E = 10.5 x 1013 N/C (b)…

A: Given: Electric field, E = 10.5 x 1013 N/C. Virtual surface area, A = 2.6 x 10-5 m2. Angle, θ = 84o.…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.02 ×…

A: (given) Electric field (E) in magnitude = 7.02 ×104 N/C (a) Electric flux through the vertical…

Q: A square that has 10 cm long edges is centered on the x axis in a region where there exists a…

Q: A uniform electric field with a magnitude of 1.25x10° N/C passes through a rectangle with sides of…

Q: A closed surface with dimensions a=b%3D0.40 m and c=0.60 m is located as in the figure below. The…

Q: The figure below shows a uniform electric field of magnitude E = 470 N/C making an angle of ? =…

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.14 x…

A: Given data electric field is E=7.14×104 N/C Unknowns: Find the electric flux on each case.

Q: The cube in the figure has edge length 1.62 m and is oriented as shown in a region of uniform…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

What is the electric flux through the surface? (Enter the magnitude.)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Consider a plane surface in a uniform electric field as in Figure P24.48, where d = 15.0 cm and = 70.0. If the net flux through the surface is 6.00 N find the magnitude of the electric field. Figure P24.48
A circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90 × 104 N/C. The electric flux through the surface is 52 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?
Consider the uniform electric field E = (3.0ĵ + 7.0) ✕ 103 N/C. (a) What is its electric flux (in N · m2/C) through a circular area of radius 2.3 m that lies in the yz-plane? (Enter the magnitude.) (b) What is its electric flux (in N · m2/C) through a circular area of radius 2.3 m that lies 45.0° above the xy-plane? (Assume that the unit normal vector is n̂ = 1/(2)1/2(î+k). )
A uniform electric field with a magnitude of 1.25x105 N/C passes through a rectangle with sides of 2.50 m and 5.0 m . If the electric flux through the rectangle is 6.6x105 Nm2/C , the vector normal to the rectangular surface ?
A uniform electric field with a magnitude of 1.25x105 N/C passes through a rectangle with sides of 2.50 m and 5.0 m . If the electric flux through the rectangle is 6.6x105 Nm2/C , find the angle between the electric field vector and the vector normal to the rectangular surface ?
What is the electric flux if a 3.2 m2 surface is inclined at 65O from the vertical to an 8.5 N/C horizontal uniform electric field? \ 25 Nm2/C 20 Nm2/C 11 Nm2/C 31 Nm2/C
A uniformly charged, straight filament 8.00 m in length has a total positive charge of 2.00 µC. An uncharged cardboard cylinder 4.70 cm in length and 10.0 cm in radius surrounds the filament at its center, with the filament as the axis of the cylinder. (a) Using reasonable approximations, find the electric field at the surface of the cylinder. magnitude: ____________ kN/C direction: radially outward or radially inward? (b) Using reasonable approximations, find the total electric flux through the cylinder.
The total electric flux from a cubical box of side 28.0 cm is 1.85 x 103 Nm2/C. What charge is enclosed by the box?
A square surface with sides of 2 m × 2m is located over the xy-plane, where a constant electric field with a magnitude of 150 Nm^2/C^2 is present. The direction of the electric field vector is parallel with the surface. What is the total electric flux present in the surface?* A) 37.5 Nm^2/C B) 75 Nm^2/C C) 300 Nm^2/C D) 600 Nm^2/C
A uniform horizontal electric field of E = (136 Î +71 Ĵ) N/C passes through an inclined plane that is 52 cm wide and 88 cm long. If the inclined plane makes an angle of 45° with the horizontal, determine the electric flux in the plane in N.m^2/C.
A uniform electric field with a magnitude of 1.25x10^5 N/C passes through arectangle with sides of 2.50 m and 5.0 m. If the electric flux through the rectangle is 6.6x10^5 Nm2/C, find the angle between the electric field vector and the vector normal to the rectangular surface?