Chemistry & Chemical Reactivity
Solutions
Chemistry & Chemical Reactivity
Collision of an electron and a positron results in formation of two γ rays. In the process, their masses are convened completely into energy.
- (a) Calculate the energy evolved from the annihilation of an electron and a positron, in kilojoules per mole.
- (b) Using Planck’s equation (Equation 6.2), determine the frequency of the γ rays emitted in this process.
(a)
Interpretation:
Energy evolved from the annihilation of an electron and a positron should be calculated.
Concept introduction:
Mass defect can be calculated using following formula,
Here
Conversion of amu to kJ
Annihilation of an electron and positron gives two gamma rays.
 Â
Mass of electron is
Mass of positron is
 Â
Here
 Â
 Â
 Â
Substitute the values in the equation
(b)
Interpretation:
Frequency of the gamma rays should be calculated using Planck’s equation.
Concept introduction:
Planck’s equation is given as:
The energy increases as the wavelength of the light decreases.
Chapter 25 Solutions
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