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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The decomposition of 87Rb occurs by which of the following processes?

  1. (a) alpha emission
  2. (b) beta emission
  3. (c) gamma emission
  4. (d) electron capture
  5. (e) positron emission

Interpretation Introduction

Interpretation:

The process by which decomposition of Rb-87 occurs has to be predicted.

Concept introduction:

  • In alpha decay, there will be lose of He nucleus in which mass number decreases by four and atomic number decreases by two.
  • In beta decay, there will be a lose of electron from nucleus (neutron turns into proton): there will be no change in mass number and atomic number increases by one.
  • In gamma emission, there will not be any change in, either atomic number or mass number.
  • A positron is like an electron with a positive charge and during positron emission a proton changes into a neutron and excess positive charge is emitted.
  • Electron capture converts a proton to a neutron.
Explanation

Reason for correct option:

The decomposition of Rb-87 takes place as,

R3787bS3887+e-10

Here there will be no change in mass number and atomic number increases by one.

In beta decay, there will be a lose of electron from nucleus (neutron turns into proton)

Thus the above equation shows a beta emission

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