Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
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Question
Chapter 26, Problem 20SP
To determine

The number of electrons per second passing through a section of the current carrying wire having a current of 0.70 A.

Expert Solution & Answer
Check Mark

Answer to Problem 20SP

Solution:

4.4×1018 electrons/s

Explanation of Solution

Given data:

The current passing through the wire is 0.70 A.

Formula used:

Write the expression for current passing through the wire:

I=qt

Here, I is the current, q is the magnitude of charge, and t is the time.

Write the expression for number of electrons:

n=qqe

Here, n is the number of electrons and qe is the magnitude of charge of one electron, thatis, 1.6×1019 C.

Explanation:

Recall the expression for currentpassing through the wire:

I=qt

Substitute 0.70 A for I and 1 s for t

0.70 A=q1 sq=0.70 C

Recall the expression for number of electrons:

n=qqe

Substitute 0.7 C for q and 1.6×1019 C for qe

n=0.7 C1.6×1019 C=4.375×1018 electrons/s4.4×1018 electrons/s

Conclusion:

Therefore, the number of electrons passing through the given section is 4.4×1018 electrons/s.

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