BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 2.7, Problem 73E

a.

To determine

To find: The inverse function of g(x)=x+3 .

Expert Solution

Answer to Problem 73E

  g1(x)=x23

Explanation of Solution

Given information: g(x)=x+3

Concept Use: Let, f be a one-to-one function with domain A and range B. Then its inverse function f1 has domain B and range A and is defining by f1(y)=xf(x)=y for any y in B.

Calculation:

First, we replace g(x) with y ,

Then,

  g(x)=x+3y=x+3y2=x+3x=y23g1(y)=y23g1(x)=x23

Thus, g1(x)=x23 .

b.

To determine

To sketch: The graph of the function g(x)=x+3 and the inverse function.

Expert Solution

Explanation of Solution

Given information: g(x)=x+3 and g1(x)=x23

Graph:

    x163213
    g(x)23014

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 2.7, Problem 73E

Interpretation:

A point on the graph of g(x) , (3,0) . The dotted line is the graph of y=x , CD is the graph of g1(x) . AB is the perpendicular on the dotted line from the point (3,0) , It intersects the CD line at point F (0,3) .

It is clear that the coordinate of E is reversed from F.

Thus, it means g(x) and g1(x) is the reflection of each other in the line y=x (Dotted line).

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