   Chapter 27, Problem 89PE

Chapter
Section
Textbook Problem

Show that if you have three polarizing filters, with the second at an angle of 45° to the first and the third at an angle of 90.0° to the first, the intensity of light passed by the first will be reduced to 25.0% of its value. (This is in contrast to having only the first and third, which reduces the intensity to zero, so that placing the second between them increases the intensity of the transmitted light.)

To determine

To Show:

That the intensity of light reduced to 25% of its value

Explanation

Given info:

Angle between first and second polarizer, θ1=45°

Angle between first and third polarizer, θ3=90°

Formula used:

The intensity of the transmitted wave is related to the incident wave by

I=Iocos2θ

Here,

I is the intensity of transmitted light

Io is the intensity of incident wave

θ is the angle between the direction of polarized light and the axis of polarizing filter

Calculation:

Let the intensity of incident light is Io.

The intensity of the wave transmitted from the second polarizer is calculated as

I=Iocos2θ1

Plugging the values in the above equation

I1=

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