Chapter 2.8, Problem 1.1ACP

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# How many neutrons are there in atoms of 18O? In each of the two isotopes of lead?

Interpretation Introduction

Interpretation: The number of neutrons present in the atom of 18O and two isotopes of lead are needed to be determined.

Concept introduction:

• The atomic number of oxygen is 16.
• The atomic number of lead is 82.
• The isotopes of lead are 204Pb and 206Pb
• Equation for mass number is,

massnumber=numberofprotons+numberofneutrons

• The numbers of protons and electrons are equal in an atom.
• The number of protons and electrons for different isotopes are equal.
• Two species are said to be isotopes if they have same atomic number but different mass number.
Explanation

The atomic number of oxygen is 8. So, the number of protons is 8.

The mass number of 18O is indicted as 18.

Equation for mass number is,

Â Â Â Â massâ€‰numberâ€‰â€‰=â€‰â€‰numberâ€‰ofâ€‰protonsâ€‰+â€‰numberâ€‰ofâ€‰neutrons

Therefore,

The number of neutrons in 18O is,

Â Â Â Â numberâ€‰ofâ€‰neutronsâ€‰=massâ€‰numberâ€‰âˆ’numberâ€‰ofâ€‰protonsâ€‰

Â Â Â Â 18âˆ’8â€‰=â€‰10

The atomic number of lead is 82. So the numbers of protons are 82.

The isotopes of lead are 204Pb and 206Pb

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