Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 28, Problem 11P
Interpretation Introduction
Interpretation:
The change in the helical twist of the DNA,
Concept introduction:
The spiral structure of deoxyribonucleic acid may be a low energy type that makes its formation
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P2. Calculate the frictional coefficient of a molecule of DNA of 20 base pairs in water at 20C; assume that the hydrodynamic behavior of the DNA itself can be approximated to be rod-like; the viscosity of the solvent is 0.01 g cm-1 s -1
4a in context to taking genomic DNA from eukaryotic cells and randomly shearing it into pieces of a constant size, why do some of the genomic DNA fragments re-nature so much more quickly than other fragments
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Why is the separation possible given that all the DNAs (in (a)) have the same molecular weight?
Chapter 28 Solutions
Biochemistry
Ch. 28 - Semiconservative or Conservative DNA Replication...Ch. 28 - The Enzymatic Activities of DNA Polymerase I (a)...Ch. 28 - Multiple Replication Forks in E. coli I Assuming...Ch. 28 - Multiple Replication Forks in E. coli II On the...Ch. 28 - Molecules of DNA Polymerase III per Cell vs....Ch. 28 - Number of Okazaki Fragments in E. coli and Human...Ch. 28 - The Roles of Helicases and Gyrases How do DNA...Ch. 28 - Human Genome Replication Rate Assume DNA...Ch. 28 - Heteroduplex DNA Formation in Recombination From...Ch. 28 - Homologous Recombination, Heteroduplex DNA, and...
Ch. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Chemical Mutagenesis of DNA Bases Show the...Ch. 28 - Prob. 14PCh. 28 - Recombination in Immunoglobulin Genes If...Ch. 28 - Helicase Unwinding of the E. coli Chromosome...Ch. 28 - Prob. 17PCh. 28 - Functional Consequences of Y-Family DNA Polymerase...Ch. 28 - Figure 28.11 depicts the eukaryotic cell cycle....Ch. 28 - Figure 28.41 gives some examples of recombination...Ch. 28 - Prob. 21PCh. 28 - Prob. 22P
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- Number of Okazaki Fragments in E. coli and Human DNA Replication Approximately how many Okazaki fragments are synthesized in the course of replicating an E. coli chromosome? How many in replicating an “averageâ€� human chromosome?arrow_forwardWhen Chargaffwas performing his experiments, the tetranucleotide hypothesis, which stated that DNA was composed of GACT nucleotide repeats, was the most widely accepted view of DNA’s composition. How did Chargaff disprove this hypothesis?arrow_forwardBiochemist Erwin Chargaff was the first to note that, in DNA, [A] = [T] and [G]= [C], equalities now called Chargaff’s rule. Using this rule, determine the percentages of all the bases in DNA that is 20% thymine.arrow_forward
- Replication:- what other enzymes are involved in the initiation phase?- explain the role of primers in this phase- how is the building of the leading strand different from that of the lagging strand?arrow_forwardQuestion- Determine the exact molecular weight of the following oligonucleotide and calculate the average molecular weight of an equivalently long oligonucleotide. What is the percent error between the two? Sequence (5’-3’) : GCT TTA GCG GTC AAG TGC TGT GCC ATT T M.W. of a nucleotide in ssDNA = 303.7 + 79.0 M.W. of base pair in dsDNA = 607.4 + 158arrow_forwardCalculating human genome If 1.5 percent of the human genome consists of protein-coding sequences, and the entire genome has 3.2x10^9, how many codons are there in the human genome? Remember that a codon is three nucleotides in length.arrow_forward
- Question:- Explain why there are very few sequence-specific DNA-binding proteins that bind to the minor groove of double-stranded DNA.arrow_forwardComposition as a mole fraction of one of a double-stranded DNA strand T = 0.22 and C = 0.30. In the light of this information, the following values are Calculate as a fraction. If the given information is used to calculate the desired value, If it is not sufficient, indicate the result as X.arrow_forwardI'm having difficulty with some homework, 6. a. The double helical structure of DNA is intrinsically unstable and easily dissociates to form two separate strands. Why? How does this affect the two key biological functions of chromosomal DNA? What would happen if the DNA helices were too stable? b. How can one measure the stability of a particular duplex DNA? Which molecular properties affect the stability?arrow_forward
- RECALL Which of the following statements is (are) true? (a) The two strands of DNA run parallel from their 5' to their 3'ends. (b) An adeninethymine base pair contains three hydrogen bonds. (c) Positively charged counterions are associated with DNA. (d) DNA base pairs are always perpendicular to the helix axis.arrow_forwardCodon-Anticodon Recognition: Base-Pairing Possibilities (Integrates with Chapter 11.) Draw base-pair structures for (a) a G:C base pair. (b) a C:G base pair. (C) a G:U base pair, and (d) a U:G base pair. Note how these various base pairs differ in the potential hydrogen-bonding patterns they present within the major groove and minor groove of a double-helical nucleic acid.arrow_forwardHelicase Unwinding of the E. coli Chromosome Hexameric helicases, such as DnaB, the MCM proteins, and papilloma virus El helicase (illustrated in Figures 16.22 to 16.25), unwind DNA by passing one strand of the DNA duplex through the central pore, using a mechanism based on ATP-dependent binding interactions with the bases of that strand. The genome of E. coli K12 consists of 4,686,137 nucleotides. Assuming that DnaB functions like papilloma virus El helicase, from the information given in Chapter 16 on ATP-coupled DNA unwinding, calculate how many molecules of ATP would be needed to completely unwind the E. coli K 12 chromosome.arrow_forward
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