   Chapter 28, Problem 66PE

Chapter
Section
Textbook Problem

Suppose you use an average of 500   kW ⋅ h of electric energy per month in your home. (a) How long would 1.00 g of mass converted to electric energy with an efficiency of 38.0% last you? (b) How many homes could be supplied at the 500   kW ⋅ h per month rate for one year by the energy from the described mass conversion?

To determine

(a)

The time 1.00gmass converted to electric energy.

Explanation

Given data:

Mass is m=1.00×103kg.

Power is P=500kW.h.

The velocity of light is c=3.00×108m/s.

Formula used:

The expression elastic power is,

P=Et

The energy released is,

EnergyReleased=(n100)mc2

Convert kWhto J.

500kWh=500kWh(103W1kW)(3600s1h)=1.80×109J

Substitute the value

To determine

(b)

The number of home that can be supplied 50 kWh for one year.

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