   Chapter 29, Problem 14PE

Chapter
Section
Textbook Problem

What is the maximum velocity of electrons ejected from a material by 80-nm photons, if they are bound to the material by 4.73 eV?

To determine

The maximum velocity of electrons ejected from material.

Explanation

Given:

Wavelength of radiation =λ=80 nm = 80×109 m

Speed of radiation =c=3×108 ms

Mass of electron =m=9.1×1031 kg

Maximum velocity of ejected electron =vmax

Energy of the radiation =E=?

Binding Energy of electrons =Wo=4.73 eV

Plank's constant =h=4.14×1015 eV s

Kinetic energy of the electrons =KEmax

Formula Used:

Energy of radiation is given as

E=hcλ

Kinetic energy of the ejected electron is given as

KEmax=EWo

Kinetic energy is given as

KEmax=(0.5)mv2max

Calculation:

Energy of radiation is given as

E=hcλ

Inserting the values

E=(4.14×1015 )(3×108)(80×109)E=15

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