   Chapter 29, Problem 27PE

Chapter
Section
Textbook Problem

Prove that, to three-digit accuracy, h = 4.14 × 10 − 15   eV ⋅ s , as stated in the text.

To determine

To show:

The three-digit accuracy, h=4.14×1015 eVs.

Explanation

Given info:

c=3.00×108 ms

h=6.63×1034 Js

Calculation:

Substituting the given values of joule in term of electron volt, we get

1J=11.6×1019 eV

Energy of photon in term of frequency and Planck's constant, we get

E=hf

Substituting the values of velocity of light and Planck's constant, we get

hf(6.63×1034 J

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