   Chapter 29, Problem 36PE

Chapter
Section
Textbook Problem

Assuming that 10.0% of a 100-W light bulb's energy output is in the visible range (typical for incandescent bulbs) with an average wavelength of 580 nm, and that the photons spread out uniformly and are not absorbed by the atmosphere, how far away would you be if 500 photons per second enter the 3.00-mm diameter pupil of your eye? (This number easily stimulates the retina.)

To determine

The distance away from 500 photons per second enter the 3.00-mm diameter pupil of your eye, assuming that 10.0% of a 100-W light bulb's energy output is in the visible range (typical for incandescent bulbs) with an average wavelength of 580 nm, and that the photons spread out uniformly and are not absorbed by the atmosphere..

Explanation

Given info:

P=100 W

h=6.63×1034 Js-1

n=500 photons-1

d=3 mm

λ=580 nm

Formula used:

The energy of the average visible photon is

EhcλρNA

Calculation:

The power in visible light production is 10.0% of 100 W,

P10100×100 WP 10 W

The energy of the average visible photon is

Ehcλ

E6.63×1034×3×108 580×109E 3.42×1019 J

The number of visible photons per second is

N10 Js13.42×1019 J(photon)1N2

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