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College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

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BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Assuming that 10.0% of a 100-W light bulb's energy output is in the visible range (typical for incandescent bulbs) with an average wavelength of 580 nm, and that the photons spread out uniformly and are not absorbed by the atmosphere, how far away would you be if 500 photons per second enter the 3.00-mm diameter pupil of your eye? (This number easily stimulates the retina.)

To determine

The distance away from 500 photons per second enter the 3.00-mm diameter pupil of your eye, assuming that 10.0% of a 100-W light bulb's energy output is in the visible range (typical for incandescent bulbs) with an average wavelength of 580 nm, and that the photons spread out uniformly and are not absorbed by the atmosphere..

Explanation

Given info:

  P=100 W

  h=6.63×1034 Js-1

  n=500 photons-1

  d=3 mm

  λ=580 nm

Formula used:

The energy of the average visible photon is

  EhcλρNA

Calculation:

The power in visible light production is 10.0% of 100 W,

  P10100×100 WP 10 W

The energy of the average visible photon is

  Ehcλ

  E6.63×1034×3×108 580×109E 3.42×1019 J

The number of visible photons per second is

  N10 Js13.42×1019 J(photon)1N2

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