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College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

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BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Integrated Concepts

The 54.0-eV electron in Example 29.7 has a 0.167-nm wavelength. If such electrons are passed through a double slit and have their first maximum at an angle of 25.0°, what is the slit separation d?

To determine

The slit separation in double slit experiment.

Explanation

Given info:

Energy of the electron = 54.0 eV

Wavelength of the electron = 0.167 nm or 1.67×10-10 m.

Angle at which the first maxima appears = 25.0º.

Maxima = m = 1 (first maxima)

Formula used:

The formula for slit separation is given by:

d=mλ/sinθ

Calculation:

Using:d=mλ/sinθ

d=mλ/sinθd=(1)(1

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