   Chapter 29, Problem 82PE

Chapter
Section
Textbook Problem

Integrated ConceptsA laser with a power output of 2.00 mW at a wavelength of 400 nm is projected onto calcium metal. (a) How many electrons per second are ejected? (b) What power is carried away by the electrons, given that the binding energy is 2.71 eV? (c) Calculate the current of ejected electrons. (d) If the photoelectric material is electrically insulated and acts like a 2.00-pF capacitor, how long will current flow before the capacitor voltage stops it?

To determine

(a)

A laser with a power output of2.00mW at a wavelength of400nm is projected onto calcium metal. Find the number of electrons ejected per second

Explanation

Given Data:

Given that a laser with a power output of2.00mW at a wavelength of400nm is projected onto calcium metal.

Formula Used:

Energy of photon is calculated as

E=hcλ

Whereh= Planck's constant

c= Speed of light

λ= Wavelength

Number of photons ejected per second is given as

Nt=PE

WhereNt= Number of protons ejected per second

E= Energy of photons

P= Power output

Calculation:

We haveλ=400nm

c=3.00×108m/s

h=6.63×1034kg.m/s

Energy of photon is calculated as follows:

E=hcλ

Substituting the values in the above equation, we get

E=(6.63×1034kg.m/s)(3

To determine

(b)

A laser with a power output of2.00mW at a wavelength of400nm is projected onto calcium metal. The number of electrons ejected per second is4.03×1015 .What power is carried away by the electrons, given that the binding energy is2.71eV

To determine

(c)

A laser with a power output of2.00mW at a wavelength of400nm is projected onto calcium metal. The number of electrons ejected per second is4.03×1015 .The binding energy is2.71eV and the power carried away by the electrons is2.55×104W . Calculate the current of ejected electrons.

To determine

(d)

How long will current flow before the capacitor voltage stops it?

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