College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 29.6, Problem 29.4QQ
To determine
The possible reactions.
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235/92U+1/0n→ 140/54Xe+94/38Sr+2 1/0n
mass of 235/92U=235.04393u
mass of 140/54Xe=139.92144u
mass of 94/38Sr=93.91523u
mass of 1/0n=1.008665u
Part A: What is the reaction energy Q of this reaction? Use c2=931.5MeV/u.
Part B:
Using fission, what mass m of uranium-235 would be necessary to supply all of the energy that the United States uses in a year, roughly 1.0×10^19J ?
The carbon isotope 14C is used for carbon dating of archeological artifacts. 14C (mass 2.34 x 10-26 kg) decays by the process known as beta decay in which the nucleus emits an electron (the beta particle) and a subatomic particle called a neutrino. In one such decay, the electron and the neutrino are emitted at right angles to each other. The electron (mass 9.11 x 10-31 kg) has a speed of 5.00 x 107 m/s and the neutrino has a momentum of 8.00 x 10-24 kg • m/s. What is the recoil speed of the nucleus?
Chapter 29 Solutions
College Physics
Ch. 29.3 - Prob. 29.1QQCh. 29.3 - What fraction of a radioactive sample has decayed...Ch. 29.3 - Prob. 29.3QQCh. 29.6 - Prob. 29.4QQCh. 29.6 - Prob. 29.5QQCh. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQ
Ch. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - A radioactive sample has an activity R. For each...Ch. 29 - Prob. 9CQCh. 29 - Prob. 10CQCh. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Using 2.3 1017 kg/m3 as the density of nuclear...Ch. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Two nuclei having the same mass number are known...Ch. 29 - Prob. 16PCh. 29 - Radon gas has a half-life of 3.83 days. If 3.00 g...Ch. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - The Mass of 56Fe is 55.934 9 u, and the mass of...Ch. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44PCh. 29 - Prob. 45PCh. 29 - Prob. 46PCh. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51APCh. 29 - Prob. 52APCh. 29 - Prob. 53APCh. 29 - Prob. 54APCh. 29 - Prob. 55APCh. 29 - Prob. 56APCh. 29 - Prob. 57APCh. 29 - Prob. 58APCh. 29 - Prob. 59APCh. 29 - Prob. 60APCh. 29 - Prob. 61APCh. 29 - Prob. 62AP
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- A particle physicist discovers a neutral particle with a mass of 2.02733 u that he assumes is two neutrons bound together. Find the binding energy. What is unreasonable about this result?arrow_forwardThis problem demonstrates that the binding energy of the electron in the ground state of a hydrogen atom is much smaller than the rest mass energies of the proton and electron. Calculate the mass equivalent in u of the 13.6-eV binding energy of an electron in a hydrogen atom, and compare this with the known mass of the hydrogen atom. Subtract the known mass of the proton from the known mass of the hydrogen atom. Take the ratio of the binding energy of the electron (13.6 eV) to the energy equivalent of the electron’s mass (0.511 MeV). Discuss how your answers confirm the stated purpose of this problem.arrow_forwardUnreasonable Results A particle physicist discovers a neutral particle with a mass at 2.02733 u that he assumes is two neutrons bound together. (a) Find the binding energy. (b) What is unreasonable about this result? (c) What assumptions are unreasonable or inconsistent?arrow_forward
- The net nuclear fusion reaction inside the Sun can be written as 41H 4He + E. The rest energy of each hydrogen atom is 938.78 MeV, and the rest energy of the helium-4 atom is 3 728.4 MeV. Calculate the percentage of the starting mass that is transformed to other forms of energy.arrow_forwardIf two nuclei are to fuse in a nuclear reaction, they must be moving fast enough so that the repulsive Coulomb force between them does not prevent them for getting within R1014mof one another. At this distance or nearer, the attractive nuclear force can overcome the Coulomb force, and the nuclei are able to fuse. (a) Find a simple formula that can be used to estimate the minimum kinetic energy the nuclei must have if they are to fuse. To keep the calculation simple, assume the two nuclei are identical and moving toward one another with the same speed v. (b) Use this minimum kinetic energy to estimate the minimum temperature a gas of the nuclei must have before a significant number of them will undergo fusion. Calculate this minimum temperature first for hydrogen and then for helium. (Hint: For fusion to occur, the minimum kinetic energy when the nuclei are far apart must be equal to the Coulomb potential energy when they are a distance R apart.)arrow_forward
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