The formula of the binary compound formed from the given pairs of elements in each case is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned. To determine: The formula of diboron trioxide.
The formula of the binary compound formed from the given pairs of elements in each case is to be stated. Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number − 8 . While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned. To determine: The formula of diboron trioxide.
Solution Summary: The author explains the formula of the binary compound formed from the given pairs of elements in each case.
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
To determine: The formula of diboron trioxide.
(b)
Interpretation Introduction
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
To determine: The formula of of arsenic pentafluoride.
(c)
Interpretation Introduction
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
To determine: The formula of of dinitrogen monoxide.
(d)
Interpretation Introduction
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
Refer to the nomenclature flowchart (Figure 3.11) to name each compound.a. XeO3 b. KClO c. CoSO4
Match the name with the correct formula for each molecule or ion listed.
tetraphosphorus hexoxide
a. P4O6 b. K3P c. AlPO4 d. K2CO3 e. PCO3 f. PPO4 g. AlP
potassium phosphide
a. P4O6 b. K3P c. AlPO4 d. K2CO3 e. PCO3 f. PPO4 g. AlP
aluminum phosphate
a. P4O6 b. K3P c. AlPO4 d. K2CO3 e. PCO3 f. PPO4 g. AlP
potassium carbonate
a. P4O6 b. K3P c. AlPO4 d. K2CO3 e. PCO3 f. PPO4 g. AlP
Write chemical formulas for compounds containing each of the following.
A.)Three iron atoms for every four oxygen atoms.
B.)One sulfur atom for every two fluorine atoms.
C.)One sulfur atom for every six fluorine atoms.
Express your answer as a chemical formula.