   Chapter 3, Problem 13P

Chapter
Section
Textbook Problem

A brick is thrown upward from the top of a building at an angle of 25° to the horizontal and with an initial speed of 15 m/s. If the brick is in flight for 3.0 s, how tall is the building?

To determine
The height of the building.

Explanation

Given info: The time of flight of the brick is 3.0s , the launch angle is 25° and the initial speed is 15m/s .

Explanation:

The time of flight of the brick is 3.0s . Thus, the vertical displacement is,

y=H

• H is the height of the building
• y is the vertical displacement

As the displacement here is downwards, it is negative.

The kinematic equation for the displacement is,

y=v0yt+12ayt2=(v0sinθ)t+12ayt2

Substitute H for y , 15m/s for v0 , 25° for θ , 3

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