Chapter 3, Problem 143AE

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404

Chapter
Section

### Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404
Textbook Problem

# The compound adrenaline contains 56.79% C, 6.56% H, 28.37% O, and 8.28% N by mass. What is the empirical formula for adrenaline?

Interpretation Introduction

Interpretation: The mass percentage of different elements in the compound adrenaline is given. Its empirical formula is to be calculated.

Concept introduction: The total number of molecules existing in a compound is depicted by the molecular formula of a compound, whereas the empirical formula of a compound gives the simplest ratio of elements present in a compound.

To determine: The empirical formula of adrenaline.

Explanation

Given

The mass percentage of different elements in adrenaline,

The mass percent of carbon (C) is 56.79% .

The mass percent of hydrogen (H) is 6.56% .

The mass percent of oxygen (O) is 28.73% .

The mass percent of nitrogen (N) is 8.28% .

The atomic mass of carbon (C) is 12g/mol .

The atomic mass of hydrogen (H) is 1g/mol .

The atomic mass of oxygen (O) is 16g/mol .

The atomic mass of nitrogen (N) is 14g/mol .

The quantity of the compound is assumed to be 100g .

Formula

The number of moles of a substance is calculated by the formula,

Numberofmoles=Givenmass%ofthesubstanceMolarmassofthesubstance

Substitute the value of the given mass and the molar mass of C , H , O and N in the above expression.

NumberofmolesofC=56

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