   Chapter 3, Problem 2P

Chapter
Section
Textbook Problem

A hiker walks 2.00 km north and then 3.00 km east, all in 2.50 hours. Calculate the magnitude and direction of the hiker’s (a) displacement (in km) and (b) average velocity (in km/h) during those 2.50 hours, (c) What was her average speed during the same time interval?

(a)

To determine
The magnitude and the direction of the displacement of the hiker when he completes the walk.

Explanation

Given info: The distance travelled in the north direction is 3.00km , the distance travelled in the east direction is 2.00km and the time taken for the climb is 2.50hours .

Explanation:

As displacement is a vector, the magnitude of the displacement vector is given by

Δr=rN2+rE2

• rN is the distance in the north direction
• rE is the distance in the east direction

Substitute 3.00km for rN and 2.00km for rE .

Δr=(3.00km)2+(2.00km)2=13.00km=3.61km

Thus, the magnitude of the displacement is 3

(b)

To determine
The magnitude and direction of the average velocity of the hiker when he completes the walk.

(c)

To determine
The average speed of the hiker when he completes the walk.

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