# Chapter 3, Problem 3.127QP

FindFindarrow_forward

### CHEMISTRY: ATOMS FIRST VOL 1 W/CON...

14th Edition
Burdge
ISBN: 9781259327933

#### Solutions

Chapter
Section
FindFindarrow_forward

### CHEMISTRY: ATOMS FIRST VOL 1 W/CON...

14th Edition
Burdge
ISBN: 9781259327933

(a)

Interpretation Introduction

Interpretation:

The number of photons produced in each pulse if the ruby laser produces 0.376 J of energy per pulse having the wavelength 633 nm in pulses with a duration of 1.00 × 109 s and the power (in watts) delivered by the laser per pulse should be calculated using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory.

Concept Introduction:

A wave is a disturbance or variation that travels through a medium transporting energy without transporting matter.  The wavelength is the distance between identical points on successive waves.  The frequency is the number of waves that pass through any particular point in 1 second.

Figure 1

The speed, wavelength and frequency of a wave are related by the equation: = λν where λ and ν are expressed in meters (m) and reciprocal seconds (s1) respectively.

Planck’s quantum theory

• Different atoms and molecules can emit or absorb energy in discreet quantities only.  The smallest amount of energy that can be emitted or absorbed in the form of electromagnetic radiation is known as quantum.
• The energy of the radiation absorbed or emitted is directly proportional to the frequency of the radiation.  The energy of radiation is expressed in terms of frequency as, = hν where, E = energy of the radiation; h = Planck’s constant (6.626 × 1034 Js); ν = frequency of radiation.

To find: The number of photons produced in each pulse if the ruby laser produces 0.376 J of energy per pulse having the wavelength 633 nm in pulses with a duration of 1.00 × 109 s using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory

(b)

Interpretation Introduction

Interpretation:

The number of photons produced in each pulse if the ruby laser produces 0.376 J of energy per pulse having the wavelength 633 nm in pulses with a duration of 1.00 × 109 s and the power (in watts) delivered by the laser per pulse should be calculated using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory.

Concept Introduction:

A wave is a disturbance or variation that travels through a medium transporting energy without transporting matter.  The wavelength is the distance between identical points on successive waves.  The frequency is the number of waves that pass through any particular point in 1 second.

Figure 1

The speed, wavelength and frequency of a wave are related by the equation: = λν where λ and ν are expressed in meters (m) and reciprocal seconds (s1) respectively.

Planck’s quantum theory

• Different atoms and molecules can emit or absorb energy in discreet quantities only.  The smallest amount of energy that can be emitted or absorbed in the form of electromagnetic radiation is known as quantum.
• The energy of the radiation absorbed or emitted is directly proportional to the frequency of the radiation.  The energy of radiation is expressed in terms of frequency as, = hν where, E = energy of the radiation; h = Planck’s constant (6.626 × 1034 Js); ν = frequency of radiation.

To find: Calculate the power (in watts) delivered by the laser per pulse using the relation between speed, wavelength and frequency of a wave and Planck’s quantum theory

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution