   Chapter 3, Problem 33AP

Chapter
Section
Textbook Problem

A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.75 m/s. If the roof is pitched at 35.0° below the horizon and the roof edge is 2.50 m above the ground, find (a) the time the baseball spends in the air, and (b) the horizontal distance from the roof edge to the point where the baseball lands on the ground.

(a)

To determine
The time the baseball spends in air.

Explanation

As the baseball falls down, the y component of the initial velocity is,

v0y=v0sinθ0

Here,

v0 is the initial velocity

θ0 is the initial angle of projection

Substitute 3.75m/s for v0 and 35.0° for θ0 .

v0=(3.75m/s)sin(35.0°)=2.15m/s

The final velocity is,

vy2=v0y22gΔyvy=v0y22gΔy

Here,

vy is the vertical velocity

v0y is the vertical component of the initial velocity

g is the acceleration due to gravity

Δy is the vertical displacement

The final velocity vy will be negative because the baseball is falling downwards

(b)

To determine
The horizontal distance from the roof edge to the point where the baseball lands in the ground.

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