Review. You are standing on the ground at the origin of a coordinate system. An airplane flies over you with constant velocity parallel to the x axis and at a fixed height of 7.60 × 10 3 m. At time t = 0, the airplane is directly above you so that the vector leading from you to it is P → 0 = 7.60 × 10 3 m . At t = 30.0 s, the position vector leading from you to the airplane is P → 30 = ( 8.04 × 10 3 i ^ + 7.60 × 10 3 j ^ ) m as suggested in Figure P3.31. Determine the magnitude and orientation of the airplane’s position vector at t = 45.0 s. Figure P3.31
Review. You are standing on the ground at the origin of a coordinate system. An airplane flies over you with constant velocity parallel to the x axis and at a fixed height of 7.60 × 10 3 m. At time t = 0, the airplane is directly above you so that the vector leading from you to it is P → 0 = 7.60 × 10 3 m . At t = 30.0 s, the position vector leading from you to the airplane is P → 30 = ( 8.04 × 10 3 i ^ + 7.60 × 10 3 j ^ ) m as suggested in Figure P3.31. Determine the magnitude and orientation of the airplane’s position vector at t = 45.0 s. Figure P3.31
Review. You are standing on the ground at the origin of a coordinate system. An airplane flies over you with constant velocity parallel to the x axis and at a fixed height of 7.60 × 103 m. At time t = 0, the airplane is directly above you so that the vector leading from you to it is
P
→
0
=
7.60
×
10
3
m
. At t = 30.0 s, the position vector leading from you to the airplane is
P
→
30
=
(
8.04
×
10
3
i
^
+
7.60
×
10
3
j
^
)
m
as suggested in Figure P3.31. Determine the magnitude and orientation of the airplane’s position vector at t = 45.0 s.
Consider the following two vectors:U = 1.3i + 2.2j + 4.1kV = -5.5i - 6.5j + 11.3k
What is the magnitude of the vector U?
What is the magnitude of the vector V?
What is the angle between U and V? Enter this as an angle between 0 and 90°.
A particle moves in the x-y plane with constant acceleration. At time t = 0 s, the position vector for the particle is d = 5.8 m x + 2.1 m y. The acceleration is given by the vector a = 8.3 m/s2 x + 7.8 m/s2 y. The velocity vector at time t = 0 s is v = 5.3 m/s x - 7.5 m/s y. Find the magnitude of the velocity vector at time t = 7.5 s. What is the angle between the velocity vector and the positive x-axis at time t = 7.5 s? What is the magnitude of the position vector at time t = 7.5 s? What is the angle between the position vector and the positive x-axis at time t = 7.5 s?
You are standing on the ground at the origin of a coordinate system. An airplane flies over you with constant velocity parallel to the x axis and at a fixed height of 7.60∗10 3m. At time t=0, the airplane is directly above you so that the vector leading from you to it is P0 =7.60∗10 3j^ m. At t=30.0s, the position vector leading from you to the airplane is P30=(8.04∗10 3i^+7.60∗10 3j^ )m . Determine the magnitude and orientation of the airplanes position vector at t=45.0s.
Chapter 3 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
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