   Chapter 3, Problem 3.56PAE Chemistry for Engineering Students

3rd Edition
Lawrence S. Brown + 1 other
ISBN: 9781285199023 Chemistry for Engineering Students

3rd Edition
Lawrence S. Brown + 1 other
ISBN: 9781285199023
Textbook Problem

A sample of H2C2O4.2H2O of mass 3.35 g is heated to drive off the waters of hydration (designated separately in the chemical formula). What mass of H2C2O4 remains once the water has been removed by heating?

Interpretation Introduction

Interpretation:

Mass of compound is found after water of hydration lost from it because of heating.

Concept Introduction:

Moles of the compounds and water of hydration are calculated using formula;

Moles = givenmass(g)molarmass

For calculating remaining mass of H2C2O4, mass of water is deducted from it.

To determine:

A sample of H2C2O4.2H2O of mass 3.35 g is heated to drive off water of hydration. What mass of H2C2O4 remains once the water has been removed by heating?

Explanation

Given:

Mass of H2C2O4.2H2O = 3.35 g.

Step 1: Converting mass to moles of H2C2O4.2H2O

Molar mass of H2C2O4.2H2O = 2×molar mass of C + 2×molar mass of H+4×molar mass of O+ 2×molar  mass of H2O

Molar mass of H2C2O4.2H2O = 2×12.0+2×1.0+4×16.0+2×18=90g/mol

Moles = 3.35g90g/mol=0

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