Chapter 3, Problem 35Q

### Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

Chapter
Section

### Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

# Consider the following generic reaction:A2B2 + 2C ⟶ 2CB + 2AWhat steps and information are necessary to perform the following determinations assuming that 1.00 × 104 molecules of A2B2 are reacted with excess C?a. mass of CB producedb. atoms of A producedc. moles of C reactedd. percent yield of CB

(a)

Interpretation Introduction

Interpretation: The steps and information needed to perform the given determinations are to be stated.

Concept introduction: Expressing molecular mass, atomic mass and formula mass in different conversion unit is known as mole.

Percent yield is the percentage ratio of actual yield to theoretical yield.

Percentyield=(ActualyieldTheoreticalyield)×100

The mass of any compound is calculated as

Massofcompound=Molesofcompound×Molarmassofcompound

Concept introduction: Expressing molecular mass, atomic mass and formula mass in different conversion unit is known as mole.

Percent yield is the percentage ratio of actual yield to theoretical yield.

Percentyield=(ActualyieldTheoreticalyield)×100

The mass of any compound is calculated as

Massofcompound=Molesofcompound×Molarmassofcompound

To determine: The steps and information needed to calculate the mass of CB produced.

Explanation

Given data

1.00Ã—1024â€‰moleculesâ€‰ofâ€‰A2B2 are reacted with excess of C

Given chemical reaction

A2B2+2Câ†’2CB+2A

The steps and information needed to calculate the mass of CB are,

• Molar mass of CB is required. It is the sum of mass of element C and B.
• Moles of CB is required. It can be calculated by multiplying the moles of reactant A2B2 by 2. The moles of reactant A2B2 is calculated as

MolesÂ ofâ€‰A2B2=1.00Ã—1024â€‰moleculesâ€‰ofâ€‰A2B2Ã—1â€‰moleâ€‰A2B26

(b)

Interpretation Introduction

Concept introduction: Expressing molecular mass, atomic mass and formula mass in different conversion unit is known as mole.

Percent yield is the percentage ratio of actual yield to theoretical yield.

Percentyield=(ActualyieldTheoreticalyield)×100

The mass of any compound is calculated as

Massofcompound=Molesofcompound×Molarmassofcompound

(c)

Interpretation Introduction

Concept introduction: Expressing molecular mass, atomic mass and formula mass in different conversion unit is known as mole.

Percent yield is the percentage ratio of actual yield to theoretical yield.

Percentyield=(ActualyieldTheoreticalyield)×100

The mass of any compound is calculated as

Massofcompound=Molesofcompound×Molarmassofcompound

(d)

Interpretation Introduction

Concept introduction: Expressing molecular mass, atomic mass and formula mass in different conversion unit is known as mole.

Percent yield is the percentage ratio of actual yield to theoretical yield.

Percentyield=(ActualyieldTheoreticalyield)×100

The mass of any compound is calculated as

Massofcompound=Molesofcompound×Molarmassofcompound

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