   Chapter 3, Problem 41AP

Chapter
Section
Textbook Problem

(a) If a person can jump a maximum horizontal distance (by using a 45° projection angle) of 3.0 m on Earth, what would be his maximum range on the Moon, where the free-fall acceleration is g/6 and g = 9.80 m/s2? (b) Repeat for Mars, where the acceleration due to gravity is 0.38g.

(a)

To determine
The maximum range of the person on the moon.

Explanation

When Δy=0m , the time is,

t=2v0yg

Here,

v0y is the vertical component of the initial velocity

g is the acceleration due to gravity

The range is given by

R=v0xt=2v0xv0yg

Here,

v0x is the horizontal component of the initial velocity

t is the time taken

The range on Earth is,

REarth=2v0xv0ygEarth

The range on Moon is,

RMoon=2v0xv0ygMoon </

(b)

To determine
The maximum range of the person on the mars.

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