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Chapter 3, Problem 41AP
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### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

#### Solutions

Chapter
Section
BuyFindarrow_forward

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# (a) If a person can jump a maximum horizontal distance (by using a 45° projection angle) of 3.0 m on Earth, what would be his maximum range on the Moon, where the free-fall acceleration is g/6 and g = 9.80 m/s2? (b) Repeat for Mars, where the acceleration due to gravity is 0.38g.

(a)

To determine
The maximum range of the person on the moon.

Explanation

When Î”y=0â€‰m , the time is,

t=2v0yg

Here,

v0y is the vertical component of the initial velocity

g is the acceleration due to gravity

The range is given by

R=v0xt=2v0xv0yg

Here,

v0x is the horizontal component of the initial velocity

t is the time taken

The range on Earth is,

REarth=2v0xv0ygEarth

The range on Moon is,

RMoon=2v0xv0ygMoon </

(b)

To determine
The maximum range of the person on the mars.

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