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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

In the following reactions, decide which reactant is oxidized and which is reduced. Designate the oxidizing agent and the reducing agent.

(a) Cr2O72– (aq) + 3 Sn2+(aq) + 14 H3O+(aq) → 2 Cr3+aq) + 3 Sn4+(aq) + 21 H2O()

(b) FeS(s) + 3 NO3(aq) + 4 H3O+(aq) → 3 NO(g) + SO42–(aq) + Fe3+(aq) + 6 H2O()

(a)

Interpretation Introduction

Interpretation:

In the given reaction, the oxidized and reduced reactant has to be decide and oxidizing and reducing agent should be designated.

Concept introduction:

An oxidizing agent gains the electrons and is reduced in a chemical reaction and it is electron acceptor.

A reducing agent loses electrons and is oxidized in a chemical reaction and it is electron donor.

The oxidation state is called as oxidation number, which describes degree of oxidation (loss of electrons) of an atom in a chemical compound. Theoretically, the oxidation state is positive, negative or zero.

Explanation

The given reaction is shown below,

  

The given compound is not a neutral compound.  Therefore the oxidation state of Cr in Cr2O72- is given below,

Net charge on Cr2O72- is equal to sum of the oxidation number of oxygen atoms. Therefore,

Net charge = Number of oxidation state of Cr atom+Number of oxidation state of oxygen atom -2 = (x) +  7(-2)

(b)

Interpretation Introduction

Interpretation:

In the given reaction, the oxidized and reduced reactant has to be decide and oxidizing and reducing agent should be designated.

Concept introduction:

An oxidizing agent gains the electrons and is reduced in a chemical reaction and it is electron acceptor.

A reducing agent loses electrons and is oxidized in a chemical reaction and it is electron donor.

The oxidation state is called as oxidation number, which describes degree of oxidation (loss of electrons) of an atom in a chemical compound. Theoretically, the oxidation state is positive, negative or zero.

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