Concept explainers
(a)
To find: The velocity and the acceleration function.
(a)
Explanation of Solution
Given: The expression position of particle is
Velocity is the derivation of the first position.
So, the expression for velocity is calculated as:
Acceleration is the second derivative of position. So,
Therefore, the velocity function is
(b)
To show: The particle always moves in positive direction.
(b)
Explanation of Solution
Set the derivative less than zero to find the values of
The bound given in the problem is
Hence, Proved
Chapter 3 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning