   Chapter 3, Problem 9P

Chapter
Section
Textbook Problem

The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?

To determine
The speed with which the puma must leave the ground to reach the height of 3.7m

Explanation

The velocity in the vertical direction becomes zero at the maximum height and the acceleration is directed downwards with a magnitude equal to the acceleration due to gravity.

So, the equation for the time taken to reach the maximum height becomes

vy=vy0+aytt=vyvy0ay=0vy0g=vy0g

The vertical displacement that occurred during this time is,

(Δy)max=(vy)avt=(vy+v0y2)t

Substitute vy0g for t .

(Δy)max=(0+v0y2)(vy0g)=v0y22g

The maximum vertical displacement is given as (Δy)max=3

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