The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined: 5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’ Concept introduction: DNA stores genetic information in a stable form that can be readily replicated. The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction. The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

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Answer 1

Question

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

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Tick the correct statements: Remember: Tautomers are structural isomers that differ from each other based on the position of the proton(s) and their double bonds. ( ) The nitrogenous bases of nucleic acids, which contain heterocyclic and analogous nuclei, can adopt different tautomeric forms involving multiple H+ that are exchangeable depending on the medium. In DNA, spontaneous formation of smaller tautomers appears to contribute to mutagenic errors during DNA replication, while in RNA, they seem to be related to increased structural and functional diversity of enzymes and RNA aptamers (research this and confirm if it is false or real) ( ) in relation to the figure, anomer 1 has beta stereochemistry with respect to the C anomeric of the pentose, and is making an N-glycosidic bond ( ) in relation to the figure, anomer 1 has alpha stereochemistry with respect to the C anomeric of the pentose, and is making an N-glycosidic bond ( ) In general, in naturally occurring nucleosides,…

2.- Draw a step by step diagram of the translation process then explain what is happening in each step a) include the role of the ribosome, tRNA, mRNA, b) where does translation begin on the transcript? c) what would be the amino acid sequence of the transcript that was created?

Need help. Contrast DNA replication with gene expression (transcription→translation)—when does each occur? What molecules are involved? How much of the DNA is utilized?

Answer 2

Question

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

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Answer 3

Question

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

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Answer 4

Question

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

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Answer 5

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 6

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 7

Chapter 30, Problem 1P

Interpretation Introduction

Interpretation: The sequence of the DNA coding strand and DNA template strand for the following mRNA sequence should be determined:

5’-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3’

Concept introduction:

DNA stores genetic information in a stable form that can be readily replicated.

The template strand is DNA strand from which mRNA is built and it serves as a template for transcription. It runs in a 3’ to 5’ direction.

The DNA strand which is not used as template for transcription is said to be a coding strand as it corresponds to the same sequence as that of mRNA, the only difference is instead of thymine, uracil is present in mRNA strand.

Answer 8

Expert Solution & Answer

Answer to Problem 1P

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

If the left chain is the coding chain, one reads from the 5’ end above downwards. So, the code is read as ‘…ATTGC…’ in this small part of the gene.

The template strand and the coding strand are complementary to each other, that is for each ‘A’ on the coding strand there is a ‘T’ on the template strand. For every ‘G’ on the coding strand there is a ‘C’ on the template strand. As in DNA replication, when a template strand is taken and a new strand is constructed, a photocopy of the original DNA coding strand is obtained. Similarly, when an RNA strand is constructed on the template strand, a copy of the DNA coding strand is obtained except for the difference of uracil being used instead of thymine in RNA. Thus, if the original DNA strand has the sequence ‘ATTGCT’, then it would get converted to ‘AUUGCU’ where everything is similar except for the replacement of ‘T’ by ‘U’.

Thus, the answer, the sequence for the coding strand for given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 12

Conclusion

For the given RNA sequence, the sequence of the coding strand is 5’-ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG-3’ and the sequence for the template strand is 3’-TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC-5’.

Answer 13

Ch. 30 - Prob. 1P Ch. 30 - Prob. 2P Ch. 30 - Prob. 3P Ch. 30 - Prob. 4P Ch. 30 - Prob. 5P Ch. 30 - Prob. 6P Ch. 30 - Prob. 7P Ch. 30 - Prob. 8P Ch. 30 - Prob. 9P Ch. 30 - Prob. 10P

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