   Chapter 30, Problem 21PE

Chapter
Section
Textbook Problem

A beryllium ion with a single electron (denoted Be3+) is in an excited state with radius the same as that of the ground state of hydrogen.(a) What is n for the Be3+ ion?(b) How much energy in eV is needed to ionize the ion from this excited state?

To determine

(a)

A beryllium ion with a single electron (denoted asBr3+ ) is in excited state with radius the same as that of the ground state of hydrogen. What isn for theBr3+ ion?

Explanation

Given Data:

Given beryllium ion with a single electron (denoted asBr3+ ) is in excited state with radius the same as that of the ground state of hydrogen.

Formula Used:

Radius of an atom is given as

rn=n2aBZ

Wherern= radius of orbit

n= Energy state

Z= Number of protons

Calculation:

Given that the Beryllium ion is in the excited state with radius the same as that of the ground state of hydrogen

We haveZ=1 andn=1

Radius of hydrogen is calculated as

rn=1

To determine

(b)

A beryllium ion with a single electron (denoted asBr3+ ) is in excited state with radius the same as that of the ground state of hydrogen. How much energy is needed to ionize the ion from this excited state?

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