Chapter 30, Problem 34PE

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

Chapter
Section

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

# Some of the most powerful lasers are based on the energy levels of neodymium in solids, such as glass, as shown in Figure 30.65. (a) What average wavelength light can pump the neodymium into the levels above its metastable state? (b) Verify that the 1.17 eV transition produces 1.06 μm radiation.Figure 30.65 Neodymium atoms in glass have these energy levels, one of which is metastable. The group of levels above the metastable state is convenient for achieving a population inversion, since photons of many different energies can be absorbed by atoms in the ground state.

To determine

(a)

The average wavelength light can pump the neodymium into the levels above its metastable state.

Explanation

Given Data:

Given energy level diagram of lasers based on energy levels of neodymium in solids such as glass.

â€ƒâ€ƒ

Formula Used:

Energy is given as

â€ƒâ€ƒE=hcÎ»

Where, E= Energy

â€ƒâ€ƒh= Planck's Constant

â€ƒâ€ƒc= Speed of light

â€ƒâ€ƒÎ»= Wavelength

Energy released during transition between metastable state and ground state is given as

â€ƒâ€ƒÎ”E=Emâˆ’Eg

Where Î”E= Energy released during the transition between two states

â€ƒâ€ƒEm= Energy of metastable state

â€ƒâ€ƒEg= Energy of ground state

Calculation:

From energy level diagram,

â€ƒâ€ƒEmabove=2.1eV

â€ƒâ€ƒEg=0eV

Energy released during transition from ground state to above metastable state is calculated as

â€ƒâ€ƒÎ”E=(2.1eV)âˆ’(0eV)

â€ƒâ€ƒÎ”E=2.1eV

Now, wavelength emitted by laser is calculated using Planck's equation

We have h=6.626Ã—10âˆ’34J.s

â€ƒâ€ƒE=2.1eV

â€ƒâ€ƒc=3Ã—108m/sec

Substituting the values in equation of energy, we have

â€ƒâ€ƒE=hcÎ»

â€ƒâ€ƒ2.1eV=(6.626Ã— 10 âˆ’34J

To determine

(b)

The 1.17eV transition produces 1.06μm radiation.

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