Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 30, Problem 86PQ
To determine
The resultant magnetic force on the electron.
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Chapter 30 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 30.2 - Prob. 30.1CECh. 30.3 - Prob. 30.2CECh. 30.4 - Prob. 30.3CECh. 30.8 - Cosmic rays are high-energy charged particles...Ch. 30.9 - The Earths Van Allen belts (Fig. 30.34) are a...Ch. 30.10 - Prob. 30.6CECh. 30.10 - Prob. 30.7CECh. 30.12 - Prob. 30.8CECh. 30 - A yoga teacher tells her students to imagine their...Ch. 30 - Prob. 2PQ
Ch. 30 - Prob. 3PQCh. 30 - Prob. 4PQCh. 30 - Prob. 5PQCh. 30 - Copy Figure P30.6 and sketch the magnetic field...Ch. 30 - Prob. 7PQCh. 30 - Prob. 9PQCh. 30 - Figure P30.10 shows a circular current-carrying...Ch. 30 - Figure P30.11 shows three configurations of wires...Ch. 30 - Review A proton is accelerated from rest through a...Ch. 30 - An electron moves in a circle of radius r at...Ch. 30 - One common type of cosmic ray is a proton...Ch. 30 - Prob. 15PQCh. 30 - Prob. 16PQCh. 30 - Prob. 17PQCh. 30 - A Two long, straight, parallel wires are shown in...Ch. 30 - Prob. 19PQCh. 30 - Two long, straight, parallel wires carry current...Ch. 30 - Prob. 21PQCh. 30 - Two long, straight wires carry the same current as...Ch. 30 - Prob. 23PQCh. 30 - A wire is bent in the form of a square loop with...Ch. 30 - Prob. 25PQCh. 30 - A Derive an expression for the magnetic field...Ch. 30 - Prob. 27PQCh. 30 - Prob. 28PQCh. 30 - Prob. 29PQCh. 30 - Prob. 30PQCh. 30 - Prob. 31PQCh. 30 - Prob. 32PQCh. 30 - Prob. 33PQCh. 30 - Prob. 34PQCh. 30 - Normally a refrigerator is not magnetized. If you...Ch. 30 - Prob. 36PQCh. 30 - Prob. 37PQCh. 30 - The magnetic field in a region is given by...Ch. 30 - Prob. 39PQCh. 30 - Prob. 40PQCh. 30 - Prob. 41PQCh. 30 - The velocity vector of a singly charged helium ion...Ch. 30 - Prob. 43PQCh. 30 - Can you use a mass spectrometer to measure the...Ch. 30 - In a laboratory experiment, a beam of electrons is...Ch. 30 - Prob. 46PQCh. 30 - Prob. 47PQCh. 30 - Prob. 48PQCh. 30 - A proton and a helium nucleus (consisting of two...Ch. 30 - Two ions are accelerated from rest in a mass...Ch. 30 - Prob. 51PQCh. 30 - Prob. 52PQCh. 30 - A rectangular silver strip is 2.50 cm wide and...Ch. 30 - For both sketches in Figure P30.56, there is a...Ch. 30 - A 1.40-m section of a straight wire oriented along...Ch. 30 - Professor Edward Ney was the founder of infrared...Ch. 30 - Prob. 59PQCh. 30 - A wire with a current of I = 8.00 A directed along...Ch. 30 - Prob. 61PQCh. 30 - The triangular loop of wire shown in Figure P30.62...Ch. 30 - Prob. 63PQCh. 30 - Consider the wires described in Problem 63. Find...Ch. 30 - Prob. 65PQCh. 30 - Prob. 66PQCh. 30 - A Three parallel current-carrying wires are shown...Ch. 30 - Prob. 68PQCh. 30 - Prob. 69PQCh. 30 - Prob. 70PQCh. 30 - Prob. 71PQCh. 30 - Prob. 72PQCh. 30 - A circular coil 15.0 cm in radius and composed of...Ch. 30 - Prob. 74PQCh. 30 - Prob. 75PQCh. 30 - Prob. 76PQCh. 30 - Prob. 77PQCh. 30 - Two long, straight, current-carrying wires run...Ch. 30 - Prob. 79PQCh. 30 - Prob. 80PQCh. 30 - Prob. 81PQCh. 30 - Prob. 82PQCh. 30 - Two infinitely long current-carrying wires run...Ch. 30 - Prob. 84PQCh. 30 - Prob. 85PQCh. 30 - Prob. 86PQCh. 30 - A charged particle with charge q and velocity...Ch. 30 - Prob. 88PQCh. 30 - Prob. 89PQCh. 30 - A mass spectrometer (Fig. 30.40, page 956)...Ch. 30 - Three long, current-carrying wires are parallel to...Ch. 30 - Prob. 92PQCh. 30 - A current-carrying conductor PQ of mass m and...Ch. 30 - A proton enters a region with a uniform electric...
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- A thin copper rod 1.00 m long has a mass of 50.0 g. What is the minimum current in the rod that would allow it to levitate above the ground in a magnetic field of magnitude 0.100 T? (a) 1.20 A (b) 2.40 A (c) 4.90 A (d) 9.80 A (e) none of those answersarrow_forwardWhat magnetic field is required in order to confine a proton moving with a speed of 4.0 × 106 m/s to a circular orbit of radius 10 cm?arrow_forwardIn Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the plane of the rectangular loop, which carries a current I2 = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. Figure P22.43 Problems 43 and 44.arrow_forward
- Within the green dashed circle shown in Figure P23.28, the magnetic field changes with time according to the expression B = 2.00t3 − 4.00t2 + 0.800, where B is in teslas, t is in seconds, and R = 2.50 cm. When t = 2.00 s, calculate (a) the magnitude and (b) the direction of the force exerted on an electron located at point P1, which is at a distance r1 = 5.00 cm from the center of the circular field region. (c) At what instant is this force equal to zero?arrow_forwardA magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forwardRank the magnitudes of' the forces exerted on the following particles from largest to smallest. In your ranking, display any cases of equality, (a) an electron moving at 1 Mm/s perpendicular to a 1-mT magnetic field (b) an electron moving at 1 Mm/s parallel to a 1-mT magnetic field (c) an electron moving at 2 Mm/s perpendicular to a 1-mT magnetic field (d) a proton moving at 1 Mm/s perpendicular to a 1-mT magnetic field (e) a proton moving at 1 Mm/s at a 45 angle to a 1-mT magnetic fieldarrow_forward
- Calculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.arrow_forwardWithin the green dashed circle show in Figure P30.21, the magnetic field changes with time according to the expression B = 2.00t3 4.00t2 + 0.800, where B is in teslas, t is in seconds, and R = 2.50 cm. When t = 2.00 s, calculate (a) the magnitude and (b) the direction of the force exerted on an electron located at point P, which is at a distance r = 5.00 cm from the center of the circular field region. (c) At what instant is this force equal to zero? Figure P30.21arrow_forwardRank the magnitudes of the following magnetic fields from largest to smallest, noting any cases of equality. (a) the field 2 cm away from a long, straight wire carrying a current of 3 A (b) the Held at the center of a flat, compact, circular coil, 2 cm in radius, with 10 turns, carrying a current of 0.3 A (c) the field at the center of a solenoid 2 cm in radius and 200 cm long, with 1 000 turns, carrying a current of 0.3 A (d) the field at the center of a long, straight, metal bar, 2 cm in radius, carrying a current of 300 (e) a field of 1 mTarrow_forward
- A proton (charge +e, mass mp), a deuteron (charge +e, mass 2mp), and an alpha particle (charge +2e, mass 4mp) are accelerated from rest through a common potential difference V. Each of the particles enters a uniform magnetic field B, with its velocity in a direction perpendicular to B. The proton moves in a circular path of radius p. In terms of p, determine (a) the radius rd of the circular orbit for the deuteron and (b) the radius r for the alpha particle.arrow_forwardA proton (charge + e, mass mp), a deuteron (charge + e, mass 2mp), and an alpha particle (charge +2e, mass 4mp) are accelerated from rest through a common potential difference V. Each of the particles enters a uniform magnetic field B, with its velocity in a direction perpendicular to B. The proton moves in a circular path of radius rp. In terms of rp, determine (a) the radius rd of the circular orbit for the deuteron and (b) the radius ra for the alpha particle.arrow_forward
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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY