Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 30.1, Problem 1P
Interpretation Introduction
Interpretation:
HOMO and LUMO of ethylene and 1,3-butadiene for both ground and excited states.
Concept introduction:
The most important orbitals in molecules for reactivity are the two so called frontier orbitals. These are called the HOMO (highest occupied molecular orbital and LUMO (lowest unoccupied molecular orbital). The HOMO is the highest energy MO that has any electrons in it. Electrons from the HOMO are donated and mostly available for bonding. The LUMO is the next highest energy orbital (it will be empty). It is the lowest unoccupied molecular orbital which can receives electrons.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Determine absolute configuration (R or S)
How do the following factors affect absorption frequencies? A. O-H vs O-D. B. CH stretch, hybrid orbitals used by carbon
Please answer it in typewritten thank you
Which molecules below are rotational Raman active and which are inactive.
O3
CH4
NH3
H2
H2O
SiH4
CF6
C4H10
Chapter 30 Solutions
Organic Chemistry
Ch. 30.1 - Prob. 1PCh. 30.3 - Prob. 2PCh. 30.3 - Prob. 3PCh. 30.4 - Prob. 4PCh. 30.6 - What stereochemistry would you expect for the...Ch. 30.6 - Prob. 6PCh. 30.7 - Prob. 7PCh. 30.8 - Propose a mechanism to account for the fact that...Ch. 30.8 - When a 2, 6-disubstituted allyl phenyl ether is...Ch. 30.9 - Prob. 10P
Ch. 30.SE - Predict the product obtained when the following...Ch. 30.SE - Prob. 12VCCh. 30.SE - The following rearrangement of N-allyl-N,...Ch. 30.SE - Plastic photochromic sunglasses are based on the...Ch. 30.SE - Prob. 15MPCh. 30.SE - Prob. 16MPCh. 30.SE - Prob. 17MPCh. 30.SE - Prob. 18APCh. 30.SE - Prob. 19APCh. 30.SE - Prob. 20APCh. 30.SE - Prob. 21APCh. 30.SE - Prob. 22APCh. 30.SE - Prob. 23APCh. 30.SE - Prob. 24APCh. 30.SE - Prob. 25APCh. 30.SE - Prob. 26APCh. 30.SE - Prob. 27APCh. 30.SE - Prob. 28APCh. 30.SE - Propose a pericyclic mechanism to account for the...Ch. 30.SE - Prob. 30APCh. 30.SE - Prob. 31APCh. 30.SE - Prob. 32APCh. 30.SE - Prob. 33APCh. 30.SE - Bicyclohexadiene, also known as Dewar benzene, is...Ch. 30.SE - Prob. 35APCh. 30.SE - Prob. 36APCh. 30.SE - The 1H NMR spectrum of bullvalene at 100 C...Ch. 30.SE - Prob. 38APCh. 30.SE - Prob. 39APCh. 30.SE - Prob. 40APCh. 30.SE - In light of your answer to Problem 30-40, explain...
Knowledge Booster
Similar questions
- In the electron paramagnetic resonance spectrum ofthe propyl radical, C3H5, the hyperfine splitting constant is1.45 mT for coupl ing to the protons on the terminal carbonatoms and 0.406 mT for coupl ing to the protons attached tothe central carbon atom. Taking 0= 2.25 mT, use the McConnellequation to estimate the unpaired electron density on eachcarbon atom.arrow_forwardFrom the vib-rot spectrum of 1HCl 35, determine P and R branches and how they are related to the theory , e.g. rotational transitionsarrow_forwardexplain why C–O stretching occurs at 1100 cm-1 and C=O stretching occurs at 1750 cm-1arrow_forward
- do ii ( hint - micheal retron )arrow_forwardIn each of the following molecules 1-8, identify the relation between the circled hydrogen atoms as homotopic, enantiotopic, diastereotopic, heterotopic?arrow_forwardHF, HCN, CCL4 and BR2. Which would have peaks in a pure rotationally spectrumarrow_forward
- How do you determine the secular determinant and pi-electron binding energy for naphthalene? Thanks.arrow_forwardUnder C4v symmetry, which irreducible representations, if any, correspond to an IR active vibration and which ones correspond to a Raman active vibration? And which ones correspond to an IR active vibration under D2h symmetry?arrow_forwardPlease refer to the images as much as you need to. For the following hydrocarbons, pick out 5 wavenumbers for each hydrocarbon, and give it its probable assignment for its structure. You may find this link useful: https://www.sigmaaldrich.com/US/en/technical-documents/technical-article/analytical-chemistry/photometry-and-reflectometry/ir-spectrum-table o-xylene (cm-1) : 985.76, 1021.06, 1052.51, 1119.30, 1383.43, 1465.62, 1495.11, 1604.66, 2859.82, 2874.76, 2922.19, 2937.08, 2968.08, 3016.57, 3049.67, 3063.02, 3105.51 m-xylene (cm-1) : 876.16, 904.28, 1039.26, 1094.05, 1169.56, 1376.70, 1397.17, 1458.12, 1491.51, 1538.93, 1557.96, 1591.83, 1612.18, 1652.69, 2730.72, 2863.59, 2920.44, 2944.72, 3015.77, 3104.24 p-xylene (cm-1) :1023.01, 1042.16, 1102.92, 1119.19, 1219.51, 1378.51, 1455.91, 1515.82, 1557.92, 1631.57, 1889.80, 2732.29, 2868.22, 2921.93, 2976.07, 2999.25, 3018.79, 3044.59, 3093.20, 3133.55, 3134.26arrow_forward
- state which of the following molecules show a pure rational microwave absorption spectrum and explain why (a) H2O (b) CO2 (c) NH3 (d) N2O (e) Benzene (f) Cl2arrow_forwardWhich ONE of the following reflection planes is observed in the pyridine molecule? a. σd b. σh c. None of the above d. σvarrow_forwardThe percent s-character of carbon participating in a C-H bond can be established by measuring the 13C-1H coupling constant and using the following relationship: Percent s-character 5 0.2 J(13C-1H)The 13C-1H coupling constant observed for methane, for example, is 125 Hz, which gives 25% s-character, the value expected for an sp3 hybridized carbon atom. Q.) In cyclopropane, the 13C-1H coupling constant is 160 Hz. What is the hybridization of carbon in cyclopropane?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning