# Suppose the range for 5.0 MeVa ray is known to be 2.0 mm in a certain material. Does this mean that every 5.0 MeVa a ray that strikes this material travels 2.0 mm, or does the range have an average value with some statistical fluctuations in the distances traveled? Explain.

### College Physics

1st Edition
Paul Peter Urone + 1 other
Publisher: OpenStax College
ISBN: 9781938168000

### College Physics

1st Edition
Paul Peter Urone + 1 other
Publisher: OpenStax College
ISBN: 9781938168000

#### Solutions

Chapter
Section
Chapter 31, Problem 1CQ
Textbook Problem

## Suppose the range for 5.0 MeVa ray is known to be 2.0 mm in a certain material. Does this mean that every 5.0 MeVa a ray that strikes this material travels 2.0 mm, or does the range have an average value with some statistical fluctuations in the distances traveled? Explain.

Expert Solution
To determine

Whether it means that every 5.0 MeV αray that strikes this material travels 2.0mm , or the range have an average value with some statistical fluctuations in the distances traveled, suppose the range for 5.0 MeV α ray is known to be 2.0mm in a certain material

Every 5.0 MeVa a ray that strikes this material won't travel 2.0 mm.

### Explanation of Solution

Concept Used:

The distance travel by the radiation through a material is defined as the range of the radiation. The range of radiation depends upon some of the factors which includes the energy of the radiation, the material through which it travels and the type of the radiation whether alpha, beta or gamma ray. By defining these factors or by knowing these factors we can know the range of the radiation. Here it is given that range of radiation is 2 mm for a certain material, But the charged particles in the material interacts with rays and because of that ray will show some random fluctuations, so every 5.0 MeV αray won't travel 2.0mm on the same material. In the α decay the energy released in it is about MeV range. It is about 106 for a typical chemical reaction. Most of the energy is converted in kinetic energy of the α particle which moves at high speed

Conclusion:

Thus, every 5.0 MeVa a ray that strikes this material won't travel 2.0 mm.

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