   Chapter 31, Problem 34PE

Chapter
Section
Textbook Problem

A rare decay mode has been observed in which 222Ra emits a 14C nucleus. (a) The decay equation is 222 Ra → A X + 14 C . Identify the nuclide AX. (b) Find the energy emitted in the decay. The mass of 222Ra is 222.015353 u.

To determine

(a)

The nuclide for the given decay equation.

Explanation

Given:

222RaAX + 14C

Formula Used:

A = N + Z

Where A is atomic mass number

Z = Number of protons in a nucleus

X = symbol for the element

In the expression below:

XZAN

Z = Number of protons in a nucleus

X = symbol for the element

We know that

A = N + Z

Where A is atomic mass number

The decay is 22288Ra134AZX + 146C8

The atomic mass of

To determine

(b)

Energy emitted in the decay

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