BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 3.1, Problem 36E
To determine

To Find: The maximum or minimum value of the function f(t)=10t2+40t+113

Expert Solution

Answer to Problem 36E

The value of minima is f(2)=73

Explanation of Solution

Given: The function is f(t)=10t2+40t+113

Calculation:

This is a quadratic function with a=10, and b=40 . Thus, the maximum or minimum value occurs at

  x=b2a=402(10)=4020=2

Since, a>0 , the function has the minimum value

  f(2)=10(2)2+40(2)+113=73

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